Based on the amount of cheese used for the pizzas, the following are true:
- a. Mai uses 2.5 ounces of cheese per pizza.
- b. Mai will need 37.5 ounces for 15 pizzas.
<h3>Cheese used per Pizza. </h3>
This can be found as:
= Ounces of cheese used / Number of pizzas
= 10 / 4
= 2.5 ounces per pizza.
<h3 /><h3>Cheese needed for 15 pizzas. </h3>
= Number of pizzas x Cheese per pizza
= 15 x 2.5
= 37.5 ounces of cheese.
In conclusion, Mai needs 37.5 ounces of cheese to make 15 pizzas.
Find out more on unit rates at brainly.com/question/1316588.
The code chunk that lets the analyst create the phone_number column is: unite(customers, "phone_number", area_code, phone_num, sep="-"
<h3>What is a data frame?</h3>
A data frame refers to a two-dimensional array-like structure or table that is made up of rows and columns, which is typically used for storing data in R Studio using the R programming language.
In Computer programming, a data frame is a list of vectors that are all equal in length, and each column consist of values of one variable while each row consist of a set of values from each column.
<h3>The executable code in R Studio.</h3>
In this scenario, the code chunk that would be used to create a data frame that combines the two columns into a single column (phone_number) is:
- unite(customers, "phone_number", area_code, phone_num, sep="-"
Read more on data frame here: brainly.com/question/25558534
Slurred speech, slow reaction time
Based on the information given, the additional information that is needed to determine the amount of his earnings will be the number of hours at each job.
From the information given, we are told that George earns $6. 25 per hour from one part-time job and $7. 50 per hour from the other part-time job and that he works a total of 40 hours between the two jobs each week.
Therefore, the additional information required will be the number of hours at each job. This will be vital in solving the question
Learn more about gross income on:
brainly.com/question/15530787
Answer:
first what is the question
