Question

Plz write it for me how u got it ❤️On paper then send it to me

Answer 1

Answer:

See below in bold.

Step-by-step explanation:

1. x^2 - 13x - 30

We need 2 numbers whose product is -30 and whose sum = -13.

They are  -15 and + 2:

Answer is (x - 15)(x + 2).

2.   2x^2 + 4x - 126

First we can take 2 out to give:

2(x^2 + 2x - 63)

Now we need 2 numbers whose product is - 63 and sum = +2.

These are +9 and - 7 so

Answer is  2(x - 7)(x + 9).

3. -30x^3 + 3x^2 + 9x

First we can take out -3x to give

-3x(10x^2 - x - 3)

Now we want  2 numbers whose product is 10*-3  = -30 and whose sum is -1. They are  -6 and +5 so we write the above as:

-3x(10x^2 + 5x - 6x - 3)

Now we factor the parentheses by grouping:

= -3x( 5x(2x + 1) - 3(2x + 1)

= -3x(2x + 1)(5x - 3)  Answer.

The answer to the second part is 12x^2 - 13x - 21.

Part 3

1, 18.

2. 6.

3. = 5(2(-3)^2 - 3*3*4 + 4^2) - 3)) - 2(-3)(-3 + 7(4) - 1) - 3*4^2

=  5*(67) - 2(72) - 48

= 143.

4.  (11m^2 - 7) - (6m^2 + 3m - 11) + (3m^2 - m - 9)

= 11m^2 - 7 - 6m^2 - 3m + 11 + 3m^2 - m - 9

=  8m^2 - 4m - 5

A = 8, B = 4 and C = 5.