(2,-1) The intersecting point is the point where the two lines meet.
We can find this using the formula: L= ∫√1+ (y')² dx
First we want to solve for y by taking the 1/2 power of both sides:
y=(4(x+1)³)^1/2
y=2(x+1)^3/2
Now, we can take the derivative using the chain rule:
y'=3(x+1)^1/2
We can then square this, so it can be plugged directly into the formula:
(y')²=(3√x+1)²
<span>(y')²=9(x+1)
</span>(y')²=9x+9
We can then plug this into the formula:
L= ∫√1+9x+9 dx *I can't type in the bounds directly on the integral, but the upper bound is 1 and the lower bound is 0
L= ∫(9x+10)^1/2 dx *use u-substitution to solve
L= ∫u^1/2 (du/9)
L= 1/9 ∫u^1/2 du
L= 1/9[(2/3)u^3/2]
L= 2/27 [(9x+10)^3/2] *upper bound is 1 and lower bound is 0
L= 2/27 [19^3/2-10^3/2]
L= 2/27 [√6859 - √1000]
L=3.792318765
The length of the curve is 2/27 [√6859 - √1000] or <span>3.792318765 </span>units.
Answer:
41.88
Step-by-step explanation:
3.49*12=41.88
Answer:
Step-by-step explanation:
The distance from Q to S is 2 - (-14), or 16.
We start at point Q. Note how 3 and 5 add up to 8, which allows us to write:
R = Q + (3/8)(16), or R = -14 + 6, or R = -8.
From R to S it is (5/8)(16), or 10 units.
The directed line segment is partitioned into segments of lengths 6 and 10, whose combined length is 16, as expected.
Answer:
Step-by-step explanation:
<u>Given</u>
<u>Solving by substitution</u>
- 2x + (x - 4) = 2
- 3x - 4 = 2
- 3x = 6
- x = 2
<u>Then finding y</u>
Intersection point is (2, -2)
