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bezimeni [28]
3 years ago
5

How do you round 44.981 using three significant figures.

Chemistry
1 answer:
sveta [45]3 years ago
3 0
Three significant figures would be 45.0 since it would end with the nine so you look at the next digit to see if you round up or it remains the same. It is greater than five so round up to zero. This makes the ones place also go up so the answer is 45.0 The zero after the decimal counts as a significant figure.
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An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams
tensa zangetsu [6.8K]

Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

⇒ y = (32×24) / 16

y= 48.0

So atomic mass of X is 48.0 amu

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3 years ago
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qwelly [4]

Answer:

+1, lose, 1, 4s, 4s and 3d

Explanation:

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