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yanalaym [24]
3 years ago
14

Dude, What ⬆the b****direct dnt think thru jobs

Chemistry
1 answer:
sammy [17]3 years ago
7 0

Answer:

Just make it sound right please it don't even add up what was you even thinking like come on now...lol

Explanation:

What does this mean I don't understand your question.

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What is the percentage of water in hydrated calcium chloride​
earnstyle [38]

Answer:

24.5%

Explanation:

You just add up the atomic masses.  

Ca - 40.078  

Cl2 - 35.4527 x 2 = 70.9054  

------ 110.9834  

H4 - 1.00794 x 4 = 4.03176  

O2 - 31.9998  

------ 36.03056  

TOTAL - 147.01396  

So the water is 36.03056/147.01396 = .245082576 but that is only accurate to three decimals (because the mass of Ca was only given to three decimals) so we write .245 and that is 24.5%

This is not my answer but I found it on Yahoo answers and it was answered by Anonymous.

8 0
3 years ago
Read 2 more answers
A soluble iodide was dissolved in water. Then an excess of silver nitrate, AgNO3, was added to precipitate all of the io- dide i
Sergeeva-Olga [200]

Answer:

m_{I^-}=1.18gI^-

Explanation:

Hello,

In this case, the reaction is given as:

I^-+AgNO_3\rightarrow AgI+NO_3^-

Thus, starting by the yielded grams of silver iodide, we obtain:

n_{I^-}=2.185gAgI*\frac{1molAgI}{234.77gAgI}*\frac{1molI}{1molAgI}=9.31x10^{-3}molI^-

Which correspond to the iodide grams in the silver iodide. In such a way, by means of the law of the conservation of mass, it is known that the grams of each atom MUST remain constant before and after the chemical reaction whereas the moles do not, therefore, the mass of iodine from the silver iodide will equal the mass of iodine present in the soluble iodide, thereby:

m_{I^-}=9.31x10^{-3}molI^-\frac{127gI^-}{1molI^-} =1.18gI^-

And the rest, correspond to the iodide's metallic cation which is unknown. Such value has sense since it is lower than the initial mass of the soluble iodide which is 1.454g, so 0.272 grams correspond to the unknown cation.

Best regards.

7 0
4 years ago
A recessive trait will never express itself if a dominant trait is present. A. FALSE B. TRUE
Alchen [17]
I think it would be B
hope this works
4 0
4 years ago
Read 2 more answers
A mixture of Ar, He, and O2 has a total pressure of 1,015 kPa. Argon exerts a partial pressure of 152 kPa and Helium exerts a pa
arsen [322]
This one is easy. It's just addition and subtraction. Add the partial pressure of Argon and the partial pressure of Helium:
   152 kPa
<u>+305 kPa</u><u>
</u>  457 kPa

Next, subtract the result from the total pressure:

  1015 kPa
<u>-  457 kPa</u>
   558 kPa
8 0
3 years ago
Which metal will more easily lose an electron sodium or potassium?
sergey [27]
<span>The metal that would more easily lose an electron would be potassium. It is more reactive than sodium. Also, looking on the periodic table, </span><span>from top to bottom for groups 1 and 2, reactivity increases. So, it should be potassium. Hope this answers the question. Have a nice day.</span>
7 0
4 years ago
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