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ivanzaharov [21]
3 years ago
5

Is sublimation heating or cooling and also deposition what is it?

Chemistry
1 answer:
Alexxandr [17]3 years ago
3 0
Deposition<span> is a </span>thermodynamic process<span>, a </span>phase transition<span> in which </span>gas<span> transforms into </span>solid<span> without passing through the </span>liquid phase<span>. The reverse of deposition is </span>sublimation   sublimation is cooling hope this helps!!
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Which of the following observations indicates that an object is falling at terminal velocity?
spayn [35]
I believe that's is answer C because your ask about and increasment on the velocity in this observation
7 0
3 years ago
When the coffee is brewed according to directions, a pound of coffee beans yields 50 cups of coffee (4 cups = 1 quart). How many
ycow [4]
About one kilogram of coffee beans is required 
3 0
3 years ago
Griffin made the following list of the different outer coverings of a plant. which part of his list is incorrect?
liraira [26]

Stamen is not an outer covering its the reproductive organ of the plants.

<h3>What is use of covering of Plants ?</h3>

Outer covering of plants is useful in protecting them from environment factors , it is useful in keeping the moisture intact inside the plants.

Among the different outer covering , Bark ,stamen , spines and fuzzy hairs

Bark , stamen and fuzzy hairs are all the outer covering of plants

Stamen is not an outer covering its the reproductive organ of the plants.

To know more about outer covering of Plants

brainly.com/question/20411910

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5 0
2 years ago
Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas​
Inessa05 [86]

The relative molecular mass of the gas​ : 64 g/mol

<h3>Further explanation</h3>

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas​

Solution

Graham's Law

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas​

Input the value :

\tt \dfrac{4r_2}{r_2}=\sqrt{\dfrac{M_2}{4} }\\\\16=\dfrac{M_2}{4}\\\\M_2=64~g/mol

7 0
3 years ago
A 10-gram aluminum cube absorbs 677 joules when its temperature is increased from 50°C to 125°C. What is the specific heat of al
ra1l [238]
<h3>Answer:</h3>

0.90J/g°C

<h3>Explanation:</h3>

We are given:

Mass of Aluminium = 10 g

Quantity of heat = 677 Joules

Change in temperature = 125°C - 50°C

                                      = 75°C

We are required to calculate the specific heat capacity of Aluminium

But, Quantity of heat = Mass × specific heat × Change in temperature

Q = mcΔt

Rearranging the formula;

c = Q ÷ mΔt

  = 677 J ÷ (10 g × 75°C)

  = 677 J ÷ 750g°C

  = 0.903 J/g°C

  = 0.90J/g°C

Thus, the specific heat capacity of Aluminium is 0.90J/g°C

8 0
3 years ago
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