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Leviafan [203]
3 years ago
6

A gas has a volume of 5.0 L at a pressure of 50 KPa. What happens to the volume when the pressure is increased to 125?

Chemistry
1 answer:
Alexeev081 [22]3 years ago
7 0
The volume becomes two. You have to use the equation P1 x V1 = P2 x V2 
P is pressure and V is volume.
P1 = 50     P2 = 125
V1 = 5       V2 = v (we don't know what it is)
Then set up the equation:
50 times 5 = 125 times v
250 = 125v
the divide both sides by 125 and isolate v
2 = v
Therefore the volume is decreased to 2.
Also, Boyle's Law explains this too: Volume and pressure are inversely related, This means that when one goes up the other goes down (ie when pressure increases volume decreases and vice versa). Becuase the pressure went up from 50 KPa tp 125 KPa the volume had to decrease.

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Match the salt with the acid and base used to form it in a neutralizing reaction. K2SO4
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Neutralization reaction:

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For example:

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1. Potassium hydroxide and sulfuric acid react to produce potassium sulfate salt and water.

2. Potassium hydroxide and phosphoric acid react to produce potassium phosphate and water.

H₃PO₄  + 3KOH  → K₃PO₄ + 3H₂O

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3 0
3 years ago
Read 2 more answers
How many moles of KClO3 reacted if 9 moles of O2 were produced in this reaction: 2KClO3 → 2KCl + 3O2
kherson [118]
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x mol KClO₃ - 9 mol O₂

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3 0
3 years ago
Given 5.0 grams of lead (II) nitrate and 3.0
natulia [17]

Answer:

                     1.70 g of NaNO₃

Explanation:

                     The balance chemical equation for given double displacement reaction is,

                               Pb(NO₃)₂ + 2 NaI → PbI₂ + 2 NaNO₃

Step 1: <u>Calculate moles of each reactant:</u>

                                   Moles =  Mass / M.Mass

For Pb(NO₃)₂:

                                   Moles =  5.0 g / 331.21 g/mol

                                   Moles =  0.0150 moles

For NaI:

                                   Moles =  3.0 g / 149.89 g/mol

                                   Moles =  0.020 moles

Step 2: <u>Calculate Limiting reagent as;</u>

According to equation,

                     1 mole of Pb(NO₃)₂ reacts with  =  2 moles of NaI

So,

              0.0150 moles of Pb(NO₃)₂ will react with  =  X moles of NaI

Solving for X,

                     X =  2 mol × 0.0150 mol / 1 mol

                     X =  0.030 moles of NaI

Hence, it means that NaI is the limiting reagent therefore, it will control the yield of Sodium Nitrate.

Step 3: <u>Find out moles of NaNO₃ formed:</u>

According to equation,

                     2 mole of NaI produced =  2 moles of NaNO₃

So,

              0.020 moles of NaI will produce   =  X moles of NaNO₃

Solving for X,

                     X =  2 mol × 0.020 mol / 2 mol

                     X =  0.020 moles of NaNO₃

Step 4: <u>Calculate Mass of NaNO₃ produced;</u>

As,                Moles  =  Mass / M.Mass

Or,

                    Mass  =  Moles × M.Mass

Putting values,

                    Mass  =  0.020 mol × 84.99 g/mol

                    Mass  =  1.70 g of NaNO₃

7 0
3 years ago
AT constant temperature, a gas is compressed from 5.5 L to 1 L. At 1 L, the pressure of the gas is 98.2 kPa. What was the origin
svet-max [94.6K]

We have that  the original pressure of this gas  is mathematically given as

P2=17.854 kPa

<h3>Boyle's law</h3>

Question Parameters:

AT constant temperature, a gas is compressed from 5.5 L to 1 L.

At 1 L, the pressure of the gas is 98.2 kPa

Generally the equation for Boyle's law   is mathematically given as

P1V1=P2V2

Therefore

P1=\frac{P2V2}{V1}\\\\P2=\frac{98.2*1}{5.5}

P2=17.854 kPa

For more information on Pressure visit

brainly.com/question/25688500

7 0
2 years ago
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