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4 years ago

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Loan for Vehicle Loan APR Payment #1 $20,000 for 66 months 2.17% $322 #2 $25,000 for 78 months 3.38% $357 #3 $30,000 for 84 mont

hs 4.35% $415 Which loan(s) would cost the borrower the most amount for the length of the loan? A) Loan #1 B) Loan #3 C) Loan #2 and #3 D) Loan #1 and #3

2 answers:

Vilka [71]4 years ago

6 0

The second loan would cost

zloy xaker [14]4 years ago

6 0

Answer: A) Loan #1

Step-by-step explanation: Usatestprep

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A rectangle and a square have the same perimeter. the rectangle is of length 6cm and has an area of 48cm², find the length of th

EleoNora [17]

<em>The length of the square that has the same perimeter as the rectangle is of length 6cm and area of 48cm² is 7cm</em>

<h2>Explanation:</h2>

Let's call:

$A_{s}:Area \ of \ square \\ \\ A_{r}:Area \ of \ rectangle \\ \\ P_{s}:Perimeter \ of \ square \\ \\ P_{r}:Perimeter \ of \ rectangle$

From the question, we know that:

<em>A rectangle and a square have the same perimeter.</em>

So:

$P_{s}=P_{r}$

Moreover:

<em>The rectangle is of length 6cm and has an area of 48cm²</em>

Accordingly:

$For \ Rectangle: \\ \\ L:Length \\ W:Width \\ \\ A_{r}=L\times W \\ \\ 48=6W \\ \\ W=8$

Also:

$A_{s}=s^2 \\ \\ S:Side \ of \ square$

From the statement of perimeters:

$P_{s}=P_{r} \\ \\ \\ But: \\ \\ P_{s}=4s \\ \\ P_{r}=2W+2L \\ \\ \\ Then: \\ \\ 4s=2W+2L \\ \\ \\ But: \ W=8 \ and \ L=6 \\ \\ 4s=2(8)+2(6) \\ \\ 4s=16+12 \\ \\ 4s=28 \\ \\ \boxed{s=7cm}$

Finally, <em>the length of the square that has the same perimeter as the rectangle is of length 6cm and area of 48cm² is 7cm</em>

<h2>Learn more:</h2>

Perimeter: brainly.com/question/9969486

#LearnWithBrainly

6 0

3 years ago

Ava wants to draw a parallelogram on the coordinate plane. She

wolverine [178]

Answer:

$k =(2,1)$

$JK = 2$

Step-by-step explanation:

Given

$J = (0,1)$ ---- $(x_1,y_1)$

$H = (1,-2)$ --- $(x_2,y_2)$

$I = (3,-2)$ --- $(x_3,y_3)$

See attachment for grid

Solving (a): The coordinates of K

The parallelogram has the following diagonals: IJ and HK

Diagonals bisect one another. So:

Midpoint of IJ = Midpoint of HK

This gives:

$\frac{1}{2}(I + J) = \frac{1}{2}(H+K)$

$\frac{1}{2}(x_3+x_1,y_3+y_1) = \frac{1}{2}(x_2+x,y_2+y)$

$\frac{1}{2}(3+0,-2+1) = \frac{1}{2}(1+x,-2+y)$

$\frac{1}{2}(3,-1) = \frac{1}{2}(1+x,-2+y)$

Multiply through by 2

$(3,-1) = (1+x,-2+y)$

By comparison:

$1 + x = 3$

$-2 + y = -1$

Solve for x and y

$x = 3 - 1 =2$

$y = -1 +2 = 1$

So, the coordinates of k is:

$k =(2,1)$

The length of JK is calculated using distance (d) formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

$J = (0,1)$ ---- $(x_1,y_1)$

$k =(2,1)$ ---- $(x_2,y_2)$

So:

$d = \sqrt{(0 - 2)^2 + (1 - 1)^2$

$d = \sqrt{(- 2)^2 + (0)^2$

$d = \sqrt{4 + 0$

$d = \sqrt{4$

$d = 2$

Hence:

$JK = 2$

8 0

3 years ago

Each of three identical jewelry boxes has two drawers. Each drawer of the first box contains a gold coin. Each drawer of the sec

Rama09 [41]

Answer:

75%

Step-by-step explanation:

75% of possibility to have gold coin

7 0

3 years ago

What is the rate of change and initial value for the linear relation that includes the points shown in the table? x; 1,3,5,7

BARSIC [14]

Answer:

The rate of change is -5

The initial value is 25

Step-by-step explanation:

Since, this is a linear relation

so, we can select any two points and find equation of line

points are (1,20) and (3,10)

so,

$x_1=1,y_1=20$

$x_2=3,y_2=10$

now, we can find slope

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{10-20}{3-1}$

$m=-5$

now, we can use point slope form of line

$y-y_1=m(x-x_1)$

now, we can plug values

$y-20=-5(x-1)$

now, we can solve for y

$y=-5x+25$

we know that

slope is the rate of change

So, the rate of change is -5

For finding initial value , we can plug x=0 and find y

$y=-5\times 0+25$

$y=25$

So, initial value is 25

3 0

3 years ago

Simplify the expression 63 + 5(4 − 2).

AURORKA [14]

68(2)
68 x 2 =
136
Your answer is 136

3 0

4 years ago