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azamat
3 years ago
15

Let U be a universal set with subsets A and B such that n(U)=118, n(A)=57, n(B′)=69, and n(A∩B)=11. Find the following:

Mathematics
1 answer:
Arturiano [62]3 years ago
4 0
n(B)=n(U)-n(B')=118-69=49\\
n(A\cup B)=n(A)+n(B)-n(A\cap B)=57+49-11=95\\
n((A\cap B)')=n(U)-n(A\cap B)=118-11=107
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Answer:

The percentage of people should be seen by the doctor between 13 and

17 minutes is 68% ⇒ 2nd term

Step-by-step explanation:

* Lets explain how to solve the problem

- Wait times at a doctor's office are typically 15 minutes, with a standard

 deviation of 2 minutes

- We want to find the  percentage of people should be seen by the

 doctor between 13 and 17 minutes

* To find the percentage we will find z-score

∵ The rule the z-score is z = (x - μ)/σ , where

# x is the score

# μ is the mean

# σ is the standard deviation

∵ The mean is 15 minutes and standard deviation is 2 minutes

∴ μ = 15 , σ = 2

∵ The people should be seen by the doctor between 13 and

   17 minutes

∵ x = 13 and 17

∴ z = \frac{13-15}{2}=\frac{-2}{2}=-1

∴ z = \frac{17-15}{2}=\frac{2}{2}=1

- Lets use the standard normal distribution table

∵ P(z > -1) = 0.15866

∵ P(z < 1) = 0.84134

∴ P(-1 < z < 1) = 0.84134 - 0.15866 = 0.68268 ≅ 0.68

∵ P(13 < x < 17) = P(-1 < z < 1)

∴ P(13 < x < 17) = 0.68 × 100% = 68%

* The percentage of people should be seen by the doctor between

  13 and 17 minutes is 68%

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