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3 years ago

1 )Before simplifying, how many terms are there in the expression 2x - 5y + 3 + x?

Mathematics

2 answers:

Liula [17]3 years ago

6 0

Answer

1)4

2)5b

3)4x 2

4)7x 2

5)y-x+z

(5 is nuber 10 on the assignment)

I hope that this helps :)

Xelga [282]3 years ago

5 0

Answer:

1. Option B, i.e., 4

2. Option C, i.e., 5b

3. Option B, i.e., $4x^2$

4. Option A, i.e, $7x^2$

5. Option C, i.e., y - x + z

Step-by-step explanation:

The given expression is

$2x-5y+3+x$

We need to find the number of terms in the given expression.

Here, the terms are 2x, -5y, 3 and x.

Therefore, the number of terms is 4. Option B is correct.

If two or more terms have same variable of same degree, then they are called like terms.

3a, a and -2a are like terms but 5b is not a like term.

Therefore, 5b cannot be combined with the others. The correct option is C.

Similarly,

-3x, x and 11x are like terms but $4x^2$ is not a like term because the degree of x is 2.

Therefore, $4x^2$ cannot be combined with the others. The correct option is B.

The given expressions are

$7x^2$

$4x+3x$

It can be rewritten as

$(4+3)x$

$7x$

It means expression 4x+3x, (4+3)x and 7x are equivalent.

Therefore, All of the following are equivalent except $7x^2$ . Option A is correct.

The given expression is

x - y + z

It can be rewritten as

x + z - y

z + x - y

z - y + x

All of the following are equivalent except y - x + z. Therefore, option C is correct.

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If 1/√a-√b=1/3 and 1/√a+√b=1/2, then find the difference of a and b.

kow [346]

ANSWER:

If $\frac{1}{\sqrt{a}-\sqrt{b}}=\frac{1}{3}$ and $\frac{1}{\sqrt{a}+\sqrt{b}}=\frac{1}{2}$ then the difference of a and b is 6

SOLUTION:

Given, $\frac{1}{\sqrt{a}-\sqrt{b}}=\frac{1}{3}$ → $\sqrt{a}-\sqrt{b}=3$ ----- (1)

And $\frac{1}{\sqrt{a}+\sqrt{b}}=\frac{1}{2}$ → $\sqrt{a}+\sqrt{b}=2$ --- (2)

We have to find difference of a and b.

Now, add (1) and (2)

$\sqrt{a}-\sqrt{b}=3$

$\sqrt{a}+\sqrt{b}=2$

Adding above two equations, we get,

$2 \sqrt{a}+0=2+3$

$\begin{array}{l}{2 \sqrt{a}=5} \\\\ {\sqrt{a}=\frac{5}{2}} \\\\ {a=\frac{25}{4}}\end{array}$

substitute $\sqrt{a}$ value in (2)

$\begin{array}{l}{\frac{5}{2}+\sqrt{b}=2} \\\\ {\sqrt{b}=\frac{2}{\sin \frac{5}{2}}} \\\\ {\sqrt{b}=\frac{4-5}{2}} \\\\ {\sqrt{b}=\frac{-1}{2}} \\\\ {b=\frac{1}{4}}\end{array}$

Now, difference of a and b is a – b = $\frac{25}{4}-\frac{1}{4}=\frac{24}{4}=6$

Hence, the difference of a and b is 6.

8 0

4 years ago

a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.

Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is $a_{n} = a^{n-1} \times r$

Step-by-step explanation:

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

The first term :

In geometric sequence, the first term is given as $a_{1}$ .

⇒ $a_{1} = 612$

Now, the geometric sequence follows as 612, 661, ........

The common ratio (r) :

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

To find the recursive rule :

A geometric series is of the form a,ar,ar2,ar3,ar4,ar5........

Here, first term $a_{1} = a$ and other terms are obtained by multiplying by r.

Observe that each term is r times the previous term.
Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form $a_{n} = a^{n-1} \times r$

This is called recursive formula for geometric sequence.

We know that r = 1.08 and $a_{1}$ = 612.

To find the second term $a_{2}$ , use the recursive rule $a_{n} = a^{n-1} \times r$

⇒ $a_{2} = a^{2-1}\times r$

⇒ $a_{2} = a^{1}\times r$

⇒ $a_{2} = 612\times 1.08$

⇒ $a_{2} = 661$

3 0

4 years ago

Please help meeeeeeee

UNO [17]

Answer - N=2 . Solve for n by simplifying both sides of the equation then isolating the variable.

4 0

3 years ago

If triangle RST is within Quadrant 4 and cos R= √3/2, what is the value of cotR

Nesterboy [21]

Answer:

CotR = -√3

Step-by-step explanation:

In the 4th quadrant, sin is negative;

Since Cos R = √3/2,

Adjacent = √3

Hypotenuse = 2

Get the opposite;

opp^2 = 2^2 -(√3)^2

opp^2 = 4 - 3

opp^2 = 1

Opp = 1

Get sinR

Sin R = opp/hyp

SinR= -1/2

CotR = cosR/sinR

CostR = (√3/2)/(-1/2)

CotR = √3/2* -2/1

CotR = -√3

6 0

3 years ago

A ferry is travelling at a constant speed back to the dock, as shown in the graph. Which

mario62 [17]

Answer:

c. y = -35*x + 105

Step-by-step explanation:

Lo que demos hacer es calcular los puntos cuando x = 0 y cuando x = 3, es decir el inicio y el fin del recorrido.

Cuando x es igual 0, y = 105, por lo tanto, la función sería:

y = A*x + 105

Cuando x = 3, y = 0, por lo tanto:

0 = 3*A + 105

resolvemos para A:

3*A = -105

A = -105/3

A = -35

Por lo tanto la función es:

y = -35*x + 105

es decir, la opción c.

7 0

3 years ago