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hram777 [196]
3 years ago
14

A bag contains 3 red marbles, 4 blue, 9 yellow, and 5 green. What is the probability of getting a yellow or a green?

Mathematics
1 answer:
galina1969 [7]3 years ago
5 0

Answer:

2/3

Step-by-step explanation:

To find the probability, you first have to add up the total number of marbles in the bag.

3+4+9+5=21

Next you find the probability of getting a yellow:

9/21

Then you find the probability of getting a green:

5/21

And since the problem says "yellow <em>or</em> green" we will add the two together

9/21 + 5/21 = 14/21 = 2/3

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I think the answer could be thank you.
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3 years ago
What is 9/10 as hundredths in fraction form and decimal form?
Arte-miy333 [17]

Answer:

see below

Step-by-step explanation:

9/10

To get as a fraction over 100, multiply the top and bottom by 10

9*10           90

------    = ------------

10*10          100

9/10   = 90/100

The decimal form for 9/10  is .9  and for 90/100 is .90

5 0
3 years ago
A spinner with 10 equally sized slices has 10 yellow slices. The dial is spun and stops on a slice at random. What is the probab
djverab [1.8K]

Answer:

1/10

Step-by-step explanation:

there are 10 slices, so if the probability of it landing on one of them is 1/10

5 0
3 years ago
Solve In standard form y+1=2/3(×+4)
kondor19780726 [428]
Standard form is another way of saying slope-intercept form. The equation you have there is in point-slope form, so we must convert this to slope-intercept form to get our final answer.

In point-slope form (y - k = m(x - h)) k is the y-value, h is the x-value, and m is the slope. All we must do is change your equation's form into standard form, or slope-intercept form which looks like this: (y = mx + b), where m is the slope and b is the y-intercept.

Convert this equation y + 1 = 2/3(x + 4) into standard/slope-intercept form.
y + 1 = 2/3(x + 4)
y + 1 = 2/3x + 2.666 Here we multiplied 2/3 by x and 4 since x + 4 is in parenthesis next to 2/3.
y + 1 - 1 = 2/3x + 2 2/3 - 1 Now we want to get y by itself so the form will look like y = mx + b, so we subtract the 1 from both sides of the equation. (2 2/3 is a mixed fraction that is equal to 2/3*4.)
y = 2/3x + 1 2/3

This is our final answer since it is in the standard, or slope-intercept form. Hope this made sense! If you have any questions please ask.
8 0
3 years ago
Solve for y where y(2)=2 and y'(2)=0 by representing y as a power series centered at x=a
Crank

I'll assume the ODE is actually

y''+(x-2)y'+y=0

Look for a series solution centered at x=2, with

y=\displaystyle\sum_{n\ge0}c_n(x-2)^n

\implies y'=\displaystyle\sum_{n\ge0}(n+1)c_{n+1}(x-2)^n

\implies y''=\displaystyle\sum_{n\ge0}(n+2)(n+1)c_{n+2}(x-2)^n

with c_0=y(2)=2 and c_1=y'(2)=0.

Substituting the series into the ODE gives

\displaystyle\sum_{n\ge0}(n+2)(n+1)c_{n+2}(x-2)^n+\sum_{n\ge0}(n+1)c_{n+1}(x-2)^{n+1}+\sum_{n\ge0}c_n(x-2)^n=0

\displaystyle\sum_{n\ge0}(n+2)(n+1)c_{n+2}(x-2)^n+\sum_{n\ge1}nc_n(x-2)^n+\sum_{n\ge0}c_n(x-2)^n=0

\displaystyle2c_2+c_0+\sum_{n\ge1}(n+2)(n+1)c_{n+2}(x-2)^n+\sum_{n\ge1}nc_n(x-2)^n+\sum_{n\ge1}c_n(x-2)^n=0

\displaystyle2c_2+c_0+\sum_{n\ge1}\bigg((n+2)(n+1)c_{n+2}+(n+1)c_n\bigg)(x-2)^n=0

\implies\begin{cases}c_0=2\\c_1=0\\(n+2)c_{n+2}+c_n=0&\text{for }n>0\end{cases}

  • If n=2k for integers k\ge0, then

k=0\implies n=0\implies c_0=c_0

k=1\implies n=2\implies c_2=-\dfrac{c_0}2=(-1)^1\dfrac{c_0}{2^1(1)}

k=2\implies n=4\implies c_4=-\dfrac{c_2}4=(-1)^2\dfrac{c_0}{2^2(2\cdot1)}

k=3\implies n=6\implies c_6=-\dfrac{c_4}6=(-1)^3\dfrac{c_0}{2^3(3\cdot2\cdot1)}

and so on, with

c_{2k}=(-1)^k\dfrac{c_0}{2^kk!}

  • If n=2k+1, we have c_{2k+1}=0 for all k\ge0 because c_1=0 causes every odd-indexed coefficient to vanish.

So we have

y(x)=\displaystyle\sum_{k\ge0}c_{2k}(x-2)^{2k}=\sum_{k\ge0}(-1)^k\frac{(x-2)^{2k}}{2^{k-1}k!}

Recall that

e^x=\displaystyle\sum_{n\ge0}\frac{x^k}{k!}

The solution we found can then be written as

y(x)=\displaystyle2\sum_{k\ge0}\frac1{k!}\left(-\frac{(x-2)^2}2\right)^k

\implies\boxed{y(x)=2e^{-(x-2)^2/2}}

6 0
3 years ago
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