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3 years ago

A bag contains 3 red marbles, 4 blue, 9 yellow, and 5 green. What is the probability of getting a yellow or a green?

Mathematics

1 answer:

galina1969 [7]3 years ago

5 0

Answer:

2/3

Step-by-step explanation:

To find the probability, you first have to add up the total number of marbles in the bag.

3+4+9+5=21

Next you find the probability of getting a yellow:

9/21

Then you find the probability of getting a green:

5/21

And since the problem says "yellow <em>or</em> green" we will add the two together

9/21 + 5/21 = 14/21 = 2/3

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3 years ago

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spin [16.1K]

Answer:

a) probability that is cracked=1/30 (3.33%)

b) probability that is discoloured = 29/600 (4.83%)

c) probability that is cracked and discoloured = 11/600 (1.83%)

Step-by-step explanation:

assuming that each stone is equally likely to be chosen then defining the events C= the stone is cracked , D= the stone is discoloured , N= the stone is neither cracked or discoloured, then

P(C)= number of favourable outcomes/total number of outcomes = 20 stones/600 stones = 1/30 (3.33%)

P(D)= number of favourable outcomes/total number of outcomes = 29 stones/600 stones = 29/600 (4.83%)

the probability that is discoloured and cracked is P(C∩D) , where

P(C∪D)=P(C) + P(D)-P(C∩D)

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P(C∪D)= 1- P(N)

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1- P(N)=P(C) + P(D)-P(C∩D)

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replacing values

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3 years ago