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liberstina [14]
3 years ago
14

Find an equation for the line that passes through the points (3,-5) and (-5,5).

Mathematics
2 answers:
kifflom [539]3 years ago
8 0

Answer:

y=-5/4 + -1.25

Step-by-step explanation:

y1 - y2 over x1 -x2

5- -5 =10

-5-3 =-8

simplify: -10/8 which is -5/4 *THAT IS YOUR SLOPE*

Now to find the y intercept pick a point. I chose (-5,5) and plug in for y=mx+b

y will be 5 ; m is your slope so -5/4 ; x is -5 and we don't have out b yet.

5=-5/4(-5) + b

multiply -5/4 and -5 = 6.25

then just subtract -5 and -6.25 = -1.25 which is your y intercept

y= -5/4 + -1.25


lawyer [7]3 years ago
8 0

Answer:

y = -⁵/₄x -⁵/₄

Step-by-step explanation:

<em>(a) Slope</em>

The point-slope formula for a straight line is

y₂ - y₁ = m(x₂ - x₁)

The line goes through the points  (3, -5) and (-5,5).

5 – (-5) =    m(-5 – 3)

       10 = -8m

       m = -⁵/₄

<em>(b) y-intercept </em>

y = mx + b

Use the point (5, -5)

    -5 = -⁵/₄×5 + b

    -5 = -²⁵/₄   + b

     b = ⁵/₄

∴  y = -⁵/₄x - ⁵/₄

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For the given question dimensions of open-top box;

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