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Lisa [10]
3 years ago
8

Please help with the problem

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

95%

Step-by-step explanation:

0.6 of 40 is 24, she bought 24 green balloons.

24 × 1.5 = 36, she bought 36 yellow balloons.

So we have

40 red

24 green

36 yellow

Then from the rest of the information, 2 red, 2 green, and 1 yellow balloon all popped.

We now have

38 red

22 green

35 yellow

for a total of:

95 balloons out of 100 original balloons, 95%

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GIVING BRAINLIEST! The triangles below are similar. How tall is the tree? Please show process.
EleoNora [17]

Answer:

Height of tree= 20

Please give me brainliest if you can

Step-by-step explanation:

x= height of tree

2/3= x/30

3x= 2(30)

3x= 60

/3    /3

x= 20

7 0
3 years ago
Read 2 more answers
An alloy is made of copper and iron by weight. 42% of it is copper and the rest is iron. If the alloy weights 55 kg, find the we
faltersainse [42]

Answer:

percent of iron in alloy= 100-42 = 58%

weight of the iron = 55×58÷100= 31.9

weight of iron= 31.9 kg

weight of copper= 55-31.9=23.1

weight of copper = 23.1

Step-by-step explanation:

[ I'm not sure but I think this is right ]

7 0
3 years ago
Read 2 more answers
Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
G(x)=2(x−3) 2 −8<br> what is the vertex of the function?
valentina_108 [34]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ g(x)=2(x-\stackrel{h}{3})^2\stackrel{k}{-8}~\hspace{10em}\stackrel{vertex}{(3,-8)}

3 0
3 years ago
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Write the equation of a line parallel to the line whose equation is 3y+5x=6 and whose y-intercept is4
victus00 [196]

Answer:

Step-by-step explanation:

Step 1:  rewrite the equation of the given line in to slope-intercept form by solving for y

  3y + 5x = 6    

     3y = -5x + 6               (subtract 5x from both sides)

        y = -(5/3)x + 2           (divide both sides by 3)

Step 2:  Our line is parallel to this line, so it has the same slope, and a

y-intercept of 4, so we have...

  y = -(5/3)x + 4      

*slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept,

 

5 0
4 years ago
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