<em>Note: Your exponential expression seems a little unclear. Because 27 is not an exponential expression.</em>
<em>But, I am assuming that your exponential expression is:
</em>
<em>The reason is that my solution would still clear your concept about this topic, no matter what the question is.
</em>
<em>
</em>
Answer:
The simplified value of the exponential expression is:
![27^{\frac{1}{3}}=3](https://tex.z-dn.net/?f=27%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D3)
Step-by-step explanation:
Assuming the exponential expression
![\:27^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5C%3A27%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\mathrm{Factor\:the\:number:\:}\:27=3^3](https://tex.z-dn.net/?f=%5Cmathrm%7BFactor%5C%3Athe%5C%3Anumber%3A%5C%3A%7D%5C%3A27%3D3%5E3)
![=\left(3^3\right)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%3D%5Cleft%283%5E3%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aexponent%5C%3Arule%7D%3A%5Cquad%20%5Cleft%28a%5Eb%5Cright%29%5Ec%3Da%5E%7Bbc%7D%2C%5C%3A%5Cquad%20%5C%3Aa%5Cge%200)
![\left(3^3\right)^{\frac{1}{3}}=3^{3\cdot \frac{1}{3}}](https://tex.z-dn.net/?f=%5Cleft%283%5E3%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D3%5E%7B3%5Ccdot%20%5Cfrac%7B1%7D%7B3%7D%7D)
![=3^{3\cdot \frac{1}{3}}](https://tex.z-dn.net/?f=%3D3%5E%7B3%5Ccdot%20%5Cfrac%7B1%7D%7B3%7D%7D)
![=3^1](https://tex.z-dn.net/?f=%3D3%5E1)
![\mathrm{Apply\:exponent\:rule}:\quad \:a^1=a](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aexponent%5C%3Arule%7D%3A%5Cquad%20%5C%3Aa%5E1%3Da)
![=3](https://tex.z-dn.net/?f=%3D3)
Therefore, the simplified value of the exponential expression is:
![27^{\frac{1}{3}}=3](https://tex.z-dn.net/?f=27%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D3)
1/12,3/12,4,12,8/12, and 9/12
for some questions helps you to solve an unknown number for algebra
cant think of example
Step-by-step explanation:
9514 1404 393
Answer:
$2038.85
Step-by-step explanation:
The value of the loan at that point is given by ...
A = P(1 +rt) . . . . . Principal P, rate r, time t (years)
A = $1850(1 + 0.1225·(10/12)) = $2038.85
Ricardo will have paid back $2038.85 at the end of the loan period.
_____
<em>Additional comment</em>
We assume that the loan accrues simple interest and that the amount due is the sum of principal and interest at the end of the loan period.
The question is not specific as to whether interest compounds, or whether intermediate (monthly) payments are made. There are many possible ways the loan could be repaid, generally involving different amounts for the different terms.
todd = 8 + 9
sally = 18 + 7
Just keep adding until they have the same amount if they ever do.
todd 17 26 35 44 53
sally 25 32 39 46 53
so it took them 5 mouths and they both have 53 CD's