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3 years ago

Can anyone help me Please and thankyou? Been struggling for 20minutes

Mathematics

2 answers:

schepotkina [342]3 years ago

5 0

There is an app that will help for these types of questions called, "Showmath."

Jlenok [28]3 years ago

3 0

We got this.

33 = $\frac{w}{4}$ + 16 so we subtract 16 to work towards isolating w.

17 = $\frac{w}{4}$ then we multiply by 4 to isolate w

68 = w

w = 68

Hope that helps! Mark Brainliest if it does. Thank you!

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Svet_ta [14]

Answer:

B-He should bisect each of the angles at the vertices of the triangular table top.

Step-by-step explanation:

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2 years ago

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Determine the equation of the circle graphed below.

sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

Find the centre of the circle.

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

$Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})$

$=(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)$

Find the radius of the circle.

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

$Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}$

$=\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6$

Therefore,

$Radius ,r = \frac{6}{2} = 3$

Standard equation of a circle:

$(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.$

Therefore , equation of the circle ;

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6 0

3 years ago

HELP ME PLEASE!!!!!!!

Diano4ka-milaya [45]

Ill take a guess of... idk. the second or the third one.

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3 years ago

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Use the number line to help you solve.

Semmy [17]

Answer:7

Step-by-step explanation:

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3 years ago

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If f(x) = x/2 plus 8 what is f(x) when x = 10

kicyunya [14]

$f(x)=\frac{x}{2}+8$

Given y = f(x)

Substitute x = 10.

$f(10)=\frac{10}{2} +8\\f(10)=5+8\\f(10)=13$

Therefore f(x) = 13 when x = 10

5 0

3 years ago