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amid [387]
3 years ago
9

)a___ is a complete binary tree such that each node in the tree contains a comparable object that us greater than or equal to th

e objects jn the nodes descendants
A. Binheap

B. Maxheap

C. Fullheap

D. Minheap
Computers and Technology
1 answer:
lesantik [10]3 years ago
7 0

Answer:

(B) Maxheap.

Explanation:

Complete binary tree:-It is a binary tree having every level filled completely excluding the last level .

Max heap:-It is a binary tree which is complete or complete binary tree in which the root node is greater than or equal to it's children or we can say descendants.So according to the question the answer is MaxHeap.

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OLga [1]
   Hey friends

The answer would be B

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3 years ago
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Which service risks our every move and routine being tracked?
lina2011 [118]
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➷ Geo tagging

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6 0
3 years ago
Write a program that prompts the user to enter in a postive number. Only accept positive numbers - if the user supplies a negati
marusya05 [52]

Answer:

The c++ program to check prime numbers is shown below.

#include <iostream>

using namespace std;

int main() {

   int num, prime=0;

   do

   {

       cout<<"Enter a positive number."<<endl;

       cin>>num;

       if(num<1)

       {

           cout<<"Invalid number. Enter a positive number"<<endl;

           cin>>num;

       }

   }while(num<1);

   

   if(num==1 || num==2 || num==3)

       cout<<num<<" is a prime number."<<endl;

   else if(num%2 == 0)

       cout<<num<<" is not a prime number."<<endl;

   else

   {

       for(int k=3; k<num/2; k++)

       {

           if(num%k == 0)

               prime++;

       }    

   if(prime>1)

       cout<<num<<" is not a prime number."<<endl;

   else

       cout<<num<<" is a prime number."<<endl;

   }

}

OUTPUT

Enter a positive number.

-7

Invalid number. Enter a positive number

0

Enter a positive number.

79

79 is a prime number.

Explanation:

The user input is validated for positivity. A do while loop along with an if statement is implemented for verification.

do

   {

       cout<<"Enter a positive number."<<endl;

       cin>>num;

       if(num<1)

       {

           cout<<"Invalid number. Enter a positive number"<<endl;

           cin>>num;

       }

   }while(num<1);

The test for prime number is done by using multiple if else statements.

If user inputs 1, 2, or 3, message is displayed.

Else If user inputs an even number, message is displayed for not prime. This is done by taking modulo of the number upon division by 2.

Else if user inputs neither an even number nor a number less than 3, the modulus of the number is taken with divisors beginning from 3 up to half of the input number.

For this, an integer variable prime is initialized to 0. A number can be completely divisible by itself or by its factors.

If the number is divisible by any of the divisors, value of variable prime is increased by 1. If value of prime is greater than 1, this means that the user input is divisible by more than one divisor. Hence, the given number is not a prime number.

5 0
3 years ago
How does Mixed Reality expand on Augmented Reality?
taurus [48]

Mixed Reality expand on Augmented Reality option d: by enabling real-time interaction between real and virtual objects.

<h3>How does mixed reality expand on augmented reality?</h3>

Mixed reality is known to be one that is made up of both augmented reality and that of augmented virtuality.

Note that Mixed reality is one that acts so as to make an environment with interactive kinds of digital objects. Augmented reality needs a screen to be able to experience the augmented experience. Mixed reality is said to be experienced via the a headset.

Hence, Mixed Reality expand on Augmented Reality option d: by enabling real-time interaction between real and virtual objects.

Learn more about Augmented Reality from

brainly.com/question/9054673

#SPJ1

3 0
2 years ago
The following code does not work as intended. It is meant to input two test grades and return the average in decimal format:
vredina [299]

Answer:

Type casting error

Explanation:

Logically, the program is correct and it is expected to return the average value. However, test1 and test2 are int values and when you applies any algebraic expression on Int, it will result into Int.

So, in this part (test1 + test2 )/2, two integers are adding and the final result is still an integer and this part will act as an integer even if you multiple or divide with any external number.

For example,

test1 = 4

test2 = 5

test1 + test2 = 9

Now, if you divide it by 2, it will still react as an integer portion. So, 9/2 would result in 4 instead of 4.5. All the calculation is done on the right side before assigning it to a double variable. Therefore, the double variable is still getting the int value and your program is not working correctly.

The solution is to typecast the "(test1 + test2 )/2" portion to double using Double.valueOf(test1 + test2)/2 ;

I have also attached the working code below.

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 System.out.println("Hello World");

 Scanner scan = new Scanner (System.in);

 int test1 = scan.nextInt();

       int test2 = scan.nextInt();

       double average = Double.valueOf(test1 + test2)/2 ;

       System.out.println("Answer: " + average);

}

}

4 0
3 years ago
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