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3 years ago

Please help...........

Computers and Technology

2 answers:

9966 [12]3 years ago

7 0

Answer:

A :is concerned with defending users’ freedom of use

C:makes source code available for editing

Hope it helps!

- miah

MrMuchimi3 years ago

4 0

Answer:

Explanation:

As a user of GPL v3 software, you have lots of freedom: You can use GPL software for commercial purposes. You can modify the software and create derivative work. You can distribute the software and any derivative work you produce, without having to ask for permission or pay

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WEP (Wired Equivalent Privacy) has a design flaw which allowed attackers to break its encryption codes, WPA2 ( 2) has not suffer

ad-work [718]

Answer:

The answer is "True"

Explanation:

In computer science, the IEEE project uses this security project, it is designed for wireless network, that provides the same level security and the data encryption for cable network also.

It provides protects in wireless transmissions from both the poking and collecting information of packets.
It also lets hackers crack their computer, that's why the given statement is true.

3 0

3 years ago

Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.

Ede4ka [16]

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

$v = \frac{(xf-xo)}{(t-to)}$

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

$t =\frac{xf}{v} =\frac{2e5 m}{2.3e8 m/s} =8.7e-4 sec.$

⇒ t = 8.7*10⁻⁴ sec.

4 0

3 years ago

Let f and g be two one-argument functions. The composition f after g is defined to be the function x 7→ f (g (x)). Define a proc

Ghella [55]

Answer and Explanation:

(define (compose f g)

(lambda (x) (f (g x))))

6 0

3 years ago

12. Write C statement(s) that accomplish the following. a. Declare int variables x and y. Initialize x to 25 and y to 18. b. Dec

saul85 [17]

Answer:

int x = 25;

int y = 18;

int temp = 10;

char ch ='a';

x += 5;

double payRate = 12.5;

int tempNum = firstNum;

int tempp = x;

x = y;

y = tempp;

printf("Value of x = %f\n",x);

printf("Value of y = %f\n",y);

printf("Arithmetic = %f\n",(x + 12/y -18));

char grade = 'A';

int a,b,c,d;

a = 5; b = 2; c = 3; d = 6;

int x = round(z);

Explanation:

The answers are straight forward.

However, I'll give a general hint in answering questions like this.

In C, variable declaration is done by:

data-type variable-name;

To declare and initialise the variable, you do;

data-type variable-name = value;

So, for questions that requires that we declare and initialise a variable, we make use of the above syntax..

Take (a) for instance:

int x = 25;

int y = 18;

Same syntax can be applied to (b), (d), (e), (h) & (I)

For question (c);

This can be done in two ways;

x = x + 5;

x+=5;

Both will give the same result.

For question (f):

We start by initialise a temporary variable that stores x.

Then we store the value of x in y.

Then we store the content of the temporary variable to y.

This swaps the values of x and y

For question (g):

When printing a double variable in C, we make use of '\f' as a string format

For question (j):

The round function is used to round up a double variable to integer.

3 0

4 years ago

You currently have 15 switches with an average of 20 stations connected to each switch. The switches are connected to one anothe

vampirchik [111]

Answer:

Reorganize the network into smaller groups and connect each group to a router.

Explanation:

The user presently has 15 switches linked to another switch, with such an avg of 20 locations. The switches are linked to each other in such a manner that almost all systems can convey within a single Local area network. The high percentage to broadcast frames were found on that Local area network. They believe the amount of broadcasts could affect throughput.

So, they would reorganize each network into smaller units and link to such a router for each unit.

4 0

3 years ago

Please help...........​

Please help...........