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son4ous [18]
3 years ago
7

I need help 50 points and brainless if you answer

Computers and Technology
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

Sure, what do you need help with

Explanation:

You might be interested in
A(n) _______ is a distributed networking architecture, residing on one or more computers, where one program requests a resource
vova2212 [387]

Answer: Client-Server model

Explanation:

The Client-server model is a distributed network application configuration, that partitions task or where one program requests a resource or service from another program, between the providers of a resource or service, called servers, and service requesters called clients. In the client-server architecture, when the client computer sends a request for data to the server through the internet, the server accepts the requested process and deliver the data packets requested back to the client.

4 0
3 years ago
A large software development company employs 100 computer programmers. Of them, 45 areproficient in Java, 30 in C, 20 in Python,
melisa1 [442]

Answer:

18, 13, 19

Explanation:

Number of computer programmers proficient only in Java = 45 - ( 1+1+6) = 37

Number of computer programmers proficient only in C++ = 30 - (6+1+5) = 18

Number of computer programmers proficient only in python = 20 - ( 1+1+5) = 13

Number of computer programmers are not proficient in any of these three languages = 100 - ( 37 + 18 + 13 + 1+ 1+ 5+ 6 ) = 100 - 81 = 19

4 0
3 years ago
Write a program that sorts an array of 10 integers using bubble sort. In the bubble sort algorithm, smaller values gradually “bu
blsea [12.9K]

Answer:

#include<iostream>

using namespace std;

int main(){

   //initialization

  int arr1[10] = {2,4,6,1,7,9,0,3,5,8};

  int temp;

   int size_arr;

   //nested for loop

  for(int i=0;i<size_arr-1;i++){

   for(int j=0;j<size_arr-i-1;j++){

       if(arr1[j]>arr1[j+1]){ //compare

               //swapping

           temp = arr1[j];

           arr1[j]=arr1[j+1];

           arr1[j+1]=temp;

       }

   }

  }

  //display the each element

  for(int i=0;i<10;i++){

   cout<<arr1[i]<<" ";

  }

    return 0;

}

Explanation:

Create the main function and declare the variable and defining the array with 10 values.

take the nested for loop, nested loop means loop inside another loop.

the outer loop traverse in the array from 0 to size-1.

and inside loop traverse from 0 to size -i-1, because for every cycle of the outer loop the one element is sorted at the end. so, we do not consider the element from the last for every cycle of the outer loop. That's why (size-i-1)

In the bubble sort, the first element compares with the second element and if the first id greater than the second then swap the value. so, for the above algorithm, we take the if statement and it checks the condition if the condition becomes true then the swap algorithm executes.

we take a third variable for swapping. after that, if the outer loop condition false it means all elements will traverse and then the loop will terminate.

and finally, take another for loop and display the output.

8 0
4 years ago
Which statement best describes what a project manager controls
I am Lyosha [343]
Project controls are processes for gathering and analyzing project data to keep costs and schedules on track. The functions of project controls include initiating, planning, monitoring and controlling, communicating, and closing out project costs and schedule.
7 0
3 years ago
Read 2 more answers
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
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