I need help 50 points and brainless if you answer

The current standard for RFID is based off of Group of answer choices MIT standards IEEE standards ISO standards there is no agr

mamaluj [8]

Answer:

ISO standards

Explanation:

ISO / IEC 14443 is the ISO standard that covers RFID usage by devices.

EPCglobal - Electronics Product Code Global Incorporated is also another international standard that covers RFID. These two standards work together to standardize RFID products produced by manufacturers so that these products can be the same across different markets and manufacturers. Example I can purchase a tag from one manufacturer and a transceiver from another and they would function well together. There are also other standards for RFID but the above two are the biggest and most popular with ISO being the oldest.

4 0

3 years ago

Jane’s company is seeking to raise their brand profile. They want to connect with an organization with a large fan base without

worty [1.4K]

Jane is looking to improve her company’s reputation through brand marketing/ social media marketing.

<h3>What Brand marketing? </h3>

This is known to be a process of setting up and growing a relationship through a brand and consumers.

Fanbase is known to be a free and monetized social network that gives anyone the right to make money through content.

Learn more about Brand marketing from

brainly.com/question/25754149

5 0

3 years ago

Which feature of a social news sharing website distinguishes it from a social bookmarking website

Crank

The privacy feature i think

4 0

4 years ago

Read 2 more answers

Given the following program: public class MysteryNumbers { public static void main(String[] args) { String one = "two"; String t

enyata [817]

Answer:

Check the explanation

Explanation:

/*Given the following program:

public class MysteryNumbers {

public static void main(String[] args) {

String one = "two";

String two = "three";

String three = "1";

int number = 20;

sentence(one, two, 3);

sentence(two, three, 14);

sentence(three, three, number + 1);

sentence(three, two, 1);

sentence("eight", three, number / 2);

}

public static void sentence(String three, String one, int number) {

System.out.println(one + " times " + three + " = " + (number * 2));

}

}*/

Write the output of each of the following calls.

sentence(one, two, 3); three times two = 6

sentence(two, three, 14); 1 times three = 28

sentence(three, three, number + 1); 1 times 1 = 42

sentence(three, two, 1); three times 1 = 2

sentence("eight", three, number / 2); 1 times eight = 20

7 0

3 years ago

Se tiene un pilar de hormigón de 30 cm de lado y 5 m de altura. Presenta una densidad de 2400 kg/m3 y una resistencia a la compr

kakasveta [241]

Answer:

El pilar no podrá soportar una masa de 10 toneladas

Explanation:

La dimensión del pilar de hormigón se da de la siguiente manera;

La longitud del lado, s = 30 cm = 0,3 m

La altura del pilar, h = 5 m

La densidad del pilar, ρ = 2,400 kg / m³

La resistencia a la compresión del pilar, σ = 500 kg / m²

El área de la sección transversal del pilar, A = s² = 0.3 m × 0.3 m = 0.09 m²

La masa del pilar, m = ρ × A × h = 2,400 × 0.09 × 5 = 1,080

La masa del pilar, m = 1.080 kg

Tenemos;

$\sigma = \dfrac{F}{A}$

Dónde;

F = La carga aplicada

A = El área de la sección transversal

∴ F = A × σ

F = 0,09 m² × 500 kg / m² = 45 kg

Por tanto, la carga que el pilar puede soportar sin compresión = 45 kg <10 toneladas = 9.071,847 kg

El pilar no podrá soportar una masa de 10 toneladas.

6 0

3 years ago