Question

What is the midpoint of the line segment with the endpoints J(–9, –4) and K(7, 8)?

Answer 1

The distance from -9 to 7 = 16 units. 
Distance from -4 to 8 = 12 units.

Divide the two values and add them to the x and y values of the first set and the result will be our midpoint.

16/2 = 8.   8 + -9 = -1
12/2 = 6.   6 + -4 = 2

So our midpoint will be (-1,2)

Answer 2

Answer:

( -1 , 2 ) is the mid point of the line segment JK.

Step-by-step explanation:

Given coordinates of the points are J( -9 , -4 ) and K( 7 , 8 )

We have to find Mid point of Line segment JK.

Coordinates of mid points are given by = $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

here $(x_1,y_1)=(-9,-4)\:\:and\:\:(x_1,y_2)=(7,8)$

So, Coordinates of the Mid Point of JK = $(\frac{-9+7}{2},\frac{-4+8}{2})$

                                                                = $(\frac{-2}{2},\frac{4}{2})$

                                                                = $(-1,2)$

Therefore, ( -1 , 2 ) is the mid point of the line segment JK.