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vekshin1
3 years ago
9

i need help A circle with radius 4 sits inside a circle with radius of 11 What is the area of the shaded region?

Mathematics
2 answers:
stiks02 [169]3 years ago
6 0
I'm guessing thet the shaded region is the outer ring.

This has area pi * 11^2 - pi * 4^2

= pi (121-16) = 105 pi  or 330 to nearest whole number.
Harlamova29_29 [7]3 years ago
5 0
If you get the area of the larger circle containing the smaller one, its area includes the smaller's circle's area.

now, if you get the area of the smaller circle and subtract it from the area of the larger circle, you're in effect making a hole in the larger circle, and what's leftover, their difference, is the are not occupied by the smaller circle, since the smaller circle's area subtraction made a hole anyway.

\bf \textit{area of a circle}\\\\
A=\pi r^2\qquad r=radius
\\\\\\
\stackrel{\textit{larger circle}}{A}=11^2\pi \implies \stackrel{\textit{larger circle}}{A}=121\pi 
\\\\\\
\stackrel{\textit{smaller circle}}{A}=4^2\pi \implies \stackrel{\textit{smaller circle}}{A}=16\pi 
\\\\\\
\stackrel{shaded~region}{A}=\stackrel{\textit{larger circle}}{A}-\stackrel{\textit{smaller circle}}{A}\implies \stackrel{shaded~region}{A}=121\pi -16\pi 
\\\\\\
\stackrel{shaded~region}{A}=105\pi
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monitta
Let number of  fives = x then number of ones = 3x  and number of tens = x - 1

so we can create the equation 

x + 3x +  x-1 + y = 26  where y = number of twenties
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5x + y = 27

also we have the equation 

5x + 3x + 10(x - 1) + 20y = 120

18x + 20y = 130..................................(1)
5x    + y    = 27     multiply  by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x  = 5,  that is  5 fives

Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y =  40
y =  2 ,   that is 2 twenties

So the answer is   there are (3x) = 15 ones , 5  fives, 4 tens and 2 twenties
7 0
4 years ago
Please help very urgent
pashok25 [27]

Answer:

y = 4x - 2

Step-by-step explanation:

8 0
3 years ago
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sasho [114]

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To evaluate (g × f)(- 1) substitute x = - 1 into the product

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3 years ago
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S_A_V [24]

Answer:

\sqrt{13}

Step-by-step explanation:

The trick here is to know the distance formula (a formula that helps you find the distance between two points).

Distance formula: distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

But now that we know this, we can simply plug in our values and solve!

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\sqrt{(6-3)^2+(5-7)^2}\\\sqrt{(3)^2+(-2)^2}\\\sqrt{9+4}\\\sqrt{13}

Now we can tell from our answer that the distance between both points is \sqrt{13}

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A 2.0- litre four - cylinder engine will have q capacity of 500cc in each of its cylinders. What would the size of this engine b
Dima020 [189]

Answer:

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