Let number of fives = x then number of ones = 3x and number of tens = x - 1
so we can create the equation
x + 3x + x-1 + y = 26 where y = number of twenties
so
5x + y = 27
also we have the equation
5x + 3x + 10(x - 1) + 20y = 120
18x + 20y = 130..................................(1)
5x + y = 27 multiply by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x = 5, that is 5 fives
Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y = 40
y = 2 , that is 2 twenties
So the answer is there are (3x) = 15 ones , 5 fives, 4 tens and 2 twenties
Answer:
y = 4x - 2
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
(g × f)(x) = g(x) × f(x) = x²(- x + 5)
To evaluate (g × f)(- 1) substitute x = - 1 into the product
x²(- x + 5)
= (- 1)²(- (- 1) + 5)
= 1(1 + 5)
= 1 × 6 = 6
Answer:

Step-by-step explanation:
The trick here is to know the distance formula (a formula that helps you find the distance between two points).
Distance formula: distance = 
But now that we know this, we can simply plug in our values and solve!

Now we can tell from our answer that the distance between both points is 
Answer:
The engine size would be 3.0 litre
Step-by-step explanation:
The given parameters are;
Volume of engine = 2.0 litre
Number of cylinders = 4
Capacity of each cylinder = 500 cc
Therefore, when 2 more 500 cc cylinders are added, the size of the engine which is the total volume of combustion gases that can be handled by the cylinders of the engine becomes;
Engine size = Total volume of engine cylinders
New engine size = (4 + 2)×500 cc = 3000 cc = 3.0 litre.