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3 years ago

Which kind of adverb is the underlined word in the sentence?

Mathematics

2 answers:

horrorfan [7]3 years ago

8 0

The answer to your question is b

Alexandra [31]3 years ago

7 0

The answer is B
Hope it helped

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Fill in the bubble completely to show your answer.

adell [148]

Answers :D18

Step-by-step explanation:

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3 years ago

2×+y=0, ×-y=6 what is the solution to this system of equations?

WITCHER [35]

2×+y=0,
×-y=6

Add the 1st to the 2nd equation==> 3x +y-y=6+0==> 3x=6 & x=2

Plug 2 into any of the equation & you will get y=-4

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4 years ago

1+231 divided by 223,123

guapka [62]

Answer:

1.0010353034

Step-by-step explanation:

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3 years ago

WWhat is the solution to the equation 1/2 X +3 equals 2/3 X plus one

RUDIKE [14]

1/2x + 3 = 2/3x + 1....multiply everything by the common denominator of 6
3x + 18 = 4x + 6
3x - 4x = 6 - 18
-x = - 12
x = 12 <====

multiplying by the common denominator will get rid of the fractions

6 0

4 years ago

Read 2 more answers

A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

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3 years ago