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puteri [66]
3 years ago
9

A football team received 3 penalties for 15 yards each, 1 for5 yards, and1 for half the distance to the goal from the 34- yard l

ine. Write and find the value of an integer expression to find the total change in their field position from these penalties.
Mathematics
1 answer:
Effectus [21]3 years ago
7 0
The first penalty they received is three 15 yards so total yards is 3(15 yards)
the second penalty is one 5 yard
the last penalty is half the 34 yard line(34 yard)/2
total change = 3(15 yards) + 5 yrad + (34 yard)/2
= 45 yards + 5 yards + 17 yards= 67yards
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2x³+4x²-2x³+x-32<br><br>A)1 B)2 C)3 D)0​
Gnoma [55]

Answer:

The degree is 2

Step-by-step explanation:

2x³ and -2x³ cancel each other out, so the expression would be 4x²+x-32.

The largest exponent value is 2, as shown in "4x²"

8 0
3 years ago
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Answer:

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2 years ago
You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,
Vsevolod [243]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

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Midpoint of BD = Midpoint of AC

\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3

The coordinates of the fourth vertex is D(4,-3)

8 0
3 years ago
A revenue department is under orders to reduce the time small business owners spend filling out pension form ABC-5500. Previousl
Goshia [24]

Considering the situation described, we have that:

  • The appropriate null hypotheses is H_0: \mu = 5.2.
  • The appropriate alternative hypotheses is H_1: \mu < 5.2.

<h3>What are the hypotheses tested?</h3>

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H_0: \mu = 5.2.

At the alternative hypothesis, it is tested if the mean has been reduced, that is, it is now of less than 5.2 hours, hence:

H_1: \mu < 5.2

More can be learned about hypotheses tests at brainly.com/question/26454209

4 0
2 years ago
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8090 [49]
Instantaneous rate of change = S'(r) = 8πr
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Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span>  is 64π
7 0
3 years ago
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