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liraira [26]
3 years ago
9

What is 38.990 rounded to the nearest integer

Mathematics
1 answer:
Elanso [62]3 years ago
7 0
39.000 if you look at the tens place (.9) it’s over 5 so you round up
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Triangle ABC is translated to triangle A'B'C' by the transformation (x,y)→(x+2,y−5) What will be the corrdinates of A'? A (4, -4
antiseptic1488 [7]

Given that: Triangle ABC is translated to triangle A'B'C' by the transformation

(x,y)\to (x+2,y-5)

The points are A(4, -4), B(2, -5), C(0, 6), D(-2, 5).

To find: Coordinates of A'.

The coordinates of A are (4,-4).

Using the given rule of transformation, we get

A(4,-4)\to A'(4+2,-4-5)

On simplification, we get

A(4,-4)\to A'(6,-9)

Therefore, the coordinates of point A' are (6,-9).

7 0
4 years ago
What is the answer to these three questions
USPshnik [31]

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x + 3 = 2(x - 6)

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dem82 [27]

Answer:

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Step-by-step explanation:

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3 years ago
Sara ​says, "If you subtract 15 from my number and multiply the difference by negative 4​, the result is negative 48​." What is
natima [27]

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4 0
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The price p and the quantity x sold of a certain product obey the demand equation p equals negative one fifth x plus 30 comma 0
Allisa [31]

Answer:

The correct answer is a) R = = - \frac{1}{5} x^{2} + 30x; b) $ 1120; c) Maximum quantity is 75 units with maximum revenue being $1125; d) p = $15.

Step-by-step explanation:

Demand equation: p = - \frac{1}{5}x + 30 , 0 \leq x \leq 150 ; where p is the price of the product and x is the quantity sold.

a) Revenue function by the problem is given to be R= p × x = - \frac{1}{5} x^{2} + 30x.

b) Revenue at x = 70 is given by 2100 - 980 = $ 1120.

c) For maximizing the R we differentiate it with respect to x and equate it to zero.

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⇒ x = 75.

As the second order derivative is negative at this point, this is the value of x that maximizes the revenue.

Maximum Revenue is at x = 75 and is equal to $1125.

d) Price charged by the company for maximum revenue is $15.

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4 years ago
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