Activity 4.4: getting a late start

The product of 3 and a number is the same as 10 less than twice the number

kicyunya [14]

Hello!

First, create a variable representing the number. In this case, let's just say n = the number.

Now, solve this by side. You can tell which is on which side of the equation by the words "is the same as". Anything before that is on one side, and anything after is on the other.

Left side: "The product of 3 and a number"

Here, we get our first side. The product means when two numbers are multiplied together. Thus, the product of 3 and a number would be 3 and a number multiplied together, or 3n.

Right side: "10 less than twice the number"

Finally, our last side. What we want to do first is "twice the number". This is because this happens first, even though the words are ordered differently. Twice the number means the number doubled, or *2. Therefore, multiply 2 and n together, to get 2n.

Next, add the "10 less" part. To do this, subtract 10 from 2n. We then get 2n - 10.

Finally, put the equation together. Take 3n and 2n-10, and create an equation. We get 3n = 2n-10.

Therefore, we have our final answer, or 3n = 2n - 10.

Hope this helps!

8 0

3 years ago

Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting t

Arturiano [62]

Answer:

You didn't give us a picture to look at

Step-by-step explanation:

7 0

3 years ago

ILL GIVE BRAINLIESSTTT

Roman55 [17]

Answer:

its "D"

Step-by-step explanation:

i used a graphing calculator

5 0

3 years ago

Use the given equation to find the number <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20x%20-%2019.7%20%3D%20

ziro4ka [17]

Answer:

x = 31.2

Step-by-step explanation:

$\frac{1}{2}$ x - 19.7 = -4.1

$\frac{1}{2}$ x = 15.6 --- add 19.7 to both sides to get rid of -19.7

x = 31.2 --- multiply both sides by 2 to get rid of $\frac{1}{2}$

7 0

2 years ago

Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe

Stolb23 [73]

Answer:

Step-by-step explanation:

The model $N (t)$ , the number of planets found up to time $t$ , as a Poisson process. So, the $N (t)$ has distribution of Poison distribution with parameter $(\lambda t)$

a)

The mean for a month is, $\lambda = \frac{1}{3}$ per month

$E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8$

(Here. t = 24)

For Poisson process mean and variance are same,

$Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8$

(Poisson distribution mean and variance equal)

The standard deviation of the number of planets is,

$\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828$

b)

For the Poisson process the intervals between events(finding a new planet) have independent exponential distribution with parameter $\lambda$ . The sum of $K$ of these independent exponential has distribution Gamma $(K, \lambda)$ .