Answer:
<h3>#1</h3>
- x² - 9 = 0
- x² = 9
- x = ± √9
- x = ± 3
Yes, -3 and 3 are zeroes of this polynomial
<h3>#2</h3>
<em>See attached graphs</em>
Zero's of a polynomial are the intersection of the graph with the x-axis.
They include coordinates as (x, 0), so the x-coordinates are zero's.
The attached shows the zero's.
<h3>#3</h3>
<em>See attached graphs</em>
Zero's of each polynomial are reflected in the graphs.
- () y = x² - x - 6 has zeros x = -2 and x = 3
- (ii) y = 6 - x - x² has zero's x = -3, x = 2
Answer:
help me pls the answer is -6
Step-by-step explanation:
To solve this, I would square root all of the possible answers and see which ones the arrow falls between. After that I would choose the answer closest to it.
Hope this helps!
Answer:
1. x2 - 9 > 0
x^2-3^2>0
(x+3)(x-3)>0
(x+3)>0 and (x-3)>0
x>-3 and x>3
2. x2 - 8x + 12 > 0
x^2 - 8x +12>0
x^2 -2x -6x +12 >0 (-8x is replaced by (-2x) + (-6x) )
x(x-2) -6(x-2) >0
(x-6)(x-2)>0
(x-6)>0 and (x-2)>0
x>6 and x>2
3. -x2 - 12x - 32 > 0
-x^2 -12x -32 >0
x^2 +12x +32 <0
x^2 +4x +8x +32<0
x(x+4) +8(x+4)<0
(x+8)(x+4)<0
(x+8)<0 and (x+4)<0
x<-8 and x<-4
4. x2 + 3x - 20 >= 3x + 5
x^2 +3x -20 >= 3x +5
x^2 +3x -20 -3x >= 3x +5 -3x
x^2 -20 >= 5
x^2 -20 +20 >= 5 +20
x^2 >=25
x^2-25 >=0
(x-5)(x+5)>=0
(x-5)>=0 and (x+5)>=0
x>=5 and x>=-5
Answer:
495 meter²
Step-by-step explanation:
In the given kite QRST,
PQ = PS = 15 meter
QR = 17 meter
We have to find the area of the kite.
Since kite is in the form of a rhombus.
and rhombus is = 
(Diagonal QS) × (Diagonal RT)
In Δ QRP,
17² = 15² + RP²
= √64 = 8 meters.
So RT = RP + PT = 8 + 25 = 33 meter.
Now area of kite = (30) (33) = 495 meter²
