-17(y - 2) = -17y + 64
Distribute the -17
-17y + 34 = -17y + 64
Add 17y to both sides
34 = 64
Once the variables cancel, and you end up with a FALSE statement, this means there are NO SOLUTIONS.
Answer: see work below
Step-by-step explanation:
1) 3(2f + 4)
distribute the 3
= 6f + 12
2) 3(4t + 2)
distribute the 3
= 12t + 6
3) 7(6k -2v)
distribute the 7
= 42k - 14v
4) 5(2q - 9)
distribute the 5
= 10q - 45
(im not sure what the red mark is. if it's a negative than my answer would be opposite: -10q + 45)
5) 3(2e + 5t)
distribute the 3
= 6e + 15t
(im not sure what the red mark is. if it's a negative my answer would be opposite: -6e -15t)
6) 4(3r - 5)
distribute the 4
= 12r - 20
Answer:
Surface area of net = 310 cm²
Step-by-step explanation:
Given:
Dimension of two same rectangle = 11 cm by 9 cm
Dimension of single rectangle = 11 cm by 7 cm
Height of two triangle = 5 Cm
Base of two triangle = 7 Cm
Find;
Surface area of net
Computation:
Surface area of net = Surface area of two same rectangle + Surface area of single rectangle + Surface area of two same triangle
Surface area of net = 2[l x b] + [l x b] + 2[(1/2)(b)(h)]
Surface area of net = 2[11 x 9] + [11 x 7] + 2[(1/2)(7)(5)]
Surface area of net = 198 + 77 + 35
Surface area of net = 310 cm²
A and b are the legs, and c is the hypotenuse.
hope this helps!
Given that the height of the ball has been modeled by h=120t-16t^2, the reasonable range will be found as follows:
maximum height is attained when h'(t)=0
given h=120t-16t^2
h'(t)=120-32t=0
thus solving for t, we get:
t=3.75 sec
thus the maximum time attained will be:
120(3.75)-16(3.75)^2=225 ft
Therefore the reasonable range will be [0≤h(t)≤225]