Question

Across a horizontal distance of 25 feet, a roller coaster has a steep drop. The height of the roller coaster at the bottom of the drop is -150 feet, compared to its height at the top of the drop.What is the average amount that the roller coaster's height changes over each horizontal foot?

Answer 1

Answer:

For each horizontal foot, the roller coaster changes 6 feet of height.

Step-by-step explanation:

Across a horizontal distance of 25 feet, a roller coaster has a steep drop.

So the run is 25 feet.

The height of the roller coaster at the bottom of the drop is -150 feet. (Negative sign is given because it is measured from the top to bottom)

So the rise is 150 feet.

The slope of the roller coaster is,

$m=\dfrac{\text{Rise}}{\text{Run}}=\dfrac{150}{25}=6$

Slope of 6 means, for 1 unit of run, the object has a rise of 6 units.

Therefore, for each horizontal foot, the roller coaster changes 6 feet of height.

Answer 2

Answer:

-6

Step-by-step explanation: You correctly divided the absolute values, but since you are dividing a negative height by a positive number of horizontal feet, the answer is negative. You still have to use the negative sign in your calculation. -150 is a real number and not to be disregarded....