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4 years ago

Prove the identity I NEED TO KNOW FAST AS POSSIBLE

Mathematics

1 answer:

antoniya [11.8K]4 years ago

5 0

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

sin²Θ = 1 - cos²Θ , cos²Θ = 1 - sin²Θ

Consider the left side

(sinΘ + cosΘ)(1 - sinΘcosΘ) ← distribute

= sinΘ(1 - sinΘcosΘ) + cosΘ(1 - sinΘcosΘ)

= sinΘ - sin²ΘcosΘ + cosΘ - sinΘcos²Θ

= sinΘ - (1 - cos²Θ)cosΘ + cosΘ - sinΘ(1 - sin²Θ)

= sinΘ - cosΘ + cos³Θ + cosΘ - sinΘ + sin³Θ ← collect like terms

= sin³Θ + cos³Θ

= right side ⇒ proven

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3 years ago

Which is the best first step when solving the following system of equations? x + y = 3. 4 x minus y = 7. Multiply the first equa

Kryger [21]

Answer:

Multiply the first equation by 4.

Step-by-step explanation:

4(x+y=3) which gives

4x+4y=12

and

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3 years ago

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-6x – 4y = -14<br> 4x – 12y = -20<br><br> a. (1, 2)<br> b. (-2, 1)<br> c. (-2,4)<br> d. (-2,-4)

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3 years ago

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3 years ago

I need to solve this system of equations, how do I do that?<br> 3x-4y=20<br> y=3/4x-5

Paha777 [63]

Answer:

Is is Infinitely many solutions so 0=0

<em><u>Step-by-step explanation:</u></em>

<h3>First we have to rearrange/simplify the equations:</h3>

Equation 1: 4y - 3x = -20

Equation (2): y - 3x/4 = -5

<h3>Then you remove the fractions by multiplication: </h3>

Multiply equation (2) by 4

<h3>The Equations now look like this: </h3>

Equation 1: 4y - 3x = -20

Equation (2): 4y - 3x = -20

<h3>Solve for y on Equation (2):</h3>

y = <u><em>3x/4 - 5</em></u>

<h3>Then plug in this for the y in Equation 1 and then solve:</h3>

4•(<u><em>3x/4-5</em></u>) - 3x = -20

Therefore the answer leads to:

Infinitely many solutions, 0=0

Hope this helped :')

4 0

3 years ago