Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.

When both machines work for 20 minutes

Machine A would produce = $\frac{20}{4} =5$ widget and

Machine B would produce = $\frac{20}{5} =4$ widgets

So we can say that Machine A would produce more widgets than Machine N at that time.

Answer is Yes

8 0

3 years ago

PLS I need help, this is due today. thank u.

mariarad [96]

Here, you would complete it with the Pythagorean Theorem.

So, A^2 + B^2 = C^2

So 14^2 + B^2 = 14^2

This equals = B = 11.49

6 0

3 years ago

Read 2 more answers

Help please!! Don’t understand! 6th grade math

Agata [3.3K]

Answer:

4. is 6.6

Step-by-step explanation:

I hope this helps

3 0

2 years ago