What type of model should be used to make a prediction from the given data?
2 answers:
Answer:
Option d. quadratic is the answer.
Step-by-step explanation:
When we plot the given points on a graph, we find that with the increase in values of x, y coordinates initially increase then decrease.
This clearly indicates to be a curve opening downwards.
A curve with its vertex as (0,0) will be represented by y = x² (Parabola).
If this curve is opening downwards that means it is y = -x²
Therefore, we can predict that the given data is of a quadratic equation.
Now we can check the graph by plotting the given points.
The given graph is representing y = -(x - 2)² + 4 which is a translated form of parent graph y = -x² (quadratic equation).
Therefore, Option d. quadratic is the answer.
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For
y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
y = (x -2)/(x^2 -49)
There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.
y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
y = (x -2)/(x^2 -49)
There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.