Answer:
Note: The full question is attached as picture below
a) Hо : p = 0.71
Ha : p ≠ 0.71
<em>p </em>= x / n
<em>p </em>= 91/110
<em>p </em>= 0.83.
1 - Pо = 1 - 0.71 = 0.29.
b) Test statistic = z
= <em>p </em>- Pо / [√Pо * (1 - Pо ) / n]
= 0.83 - 0.71 / [√(0.71 * 0.29) / 110]
= 0.12 / 0.043265
= 2.77360453
Test statistic = 2.77
c) P-value
P(z > 2.77) = 2 * [1 - P(z < 2.77)] = 2 * 0.0028
P-value = 0.0056
∝ = 0.01
P-value < ∝
Reject the null hypothesis. There is sufficient evidence to support the researchers claim at the 1% significance level.
Answer: x = 28
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Explanation:
The angles COE, EOF, and FOB combine to form angle COB
angle COB = (angleCOE)+(angleEOF)+(angleFOB)
angle COB = (3x)+(x)+(x+12)
angle COB = 5x+12
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Angles AOD and COB are vertical angles, so they are congruent
angle COB = angle AOD
5x+12 = 152
5x = 152-12
5x = 140
x = 140/5
x = 28
Answer:
A. 64/125
B. 124/125.
Step-by-step explanation:
A). As the events ( germinate or not germinate) are independent we multiply the probabilities.
Prob(All seeds germinate) = 4/5*4/5*4/5 = 64/125.
B). Probability of at least one germinating = 1 - probability that none germinate
Probability of 1 seed not germinating = 1 -45 = 1/5.
So Prob(at least one germinating)
= 1 - (1/5 * 1/5 * 1/5)
= 1 - 1/125
= 124/125.
The answer is c to your question
