Answer:
2) d= -3
5) f= -44
Step-by-step explanation:
You're welcome :)
Answer:
The volume in such a package is 27648 in³
Step-by-step explanation:
Consider the provided information.
Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in.
Let the dimension are x by x by y.
Where x is the variable for the square base package and y is the variable for length.
Thus l=x, b=x and h=y
Then the volume of the box is:
(∵V=lbh)
The maximum combined length and girth is 144.
Therefore, ![4x+y=144](https://tex.z-dn.net/?f=4x%2By%3D144)
![y=144-4x](https://tex.z-dn.net/?f=y%3D144-4x)
Substitute the value of y in volume of the box.
![V(x)=x^2(144-4x)](https://tex.z-dn.net/?f=V%28x%29%3Dx%5E2%28144-4x%29)
![V(x)=144x^2-4x^3](https://tex.z-dn.net/?f=V%28x%29%3D144x%5E2-4x%5E3)
![V'(x)=288x-12x^2](https://tex.z-dn.net/?f=V%27%28x%29%3D288x-12x%5E2)
Substitute V'(x)=0.
![0=288x-12x^2](https://tex.z-dn.net/?f=0%3D288x-12x%5E2)
![12x(24-x)=0](https://tex.z-dn.net/?f=12x%2824-x%29%3D0)
![x=0\ or\ x=24](https://tex.z-dn.net/?f=x%3D0%5C%20or%5C%20x%3D24)
Now apply second derivative test.
![V''(x)=288-24x](https://tex.z-dn.net/?f=V%27%27%28x%29%3D288-24x)
(Min)
(Max)
Hence, the maximum volume is at x=24
If x=24 then ![y=144-4(24)=48](https://tex.z-dn.net/?f=y%3D144-4%2824%29%3D48)
Substituting value of x = 24 and y = 48
gives 27648.
Hence, the volume in such a package is 27648 in³
9514 1404 393
Answer:
y = 2x -5
Step-by-step explanation:
The parallel line will differ only in the value of c. That can be found using the given point.
y = mx +c
c = y -mx . . . . . . subtract mx to solve for c
c = 1 -2·3 = -5 . . . . . . the value of m is 2 in the given equation (x, y) = (3, 1)
The equation of the parallel line is ...
y = 2x -5
<span>19095705.3333 is the answer
hope i helped!</span>