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2 years ago

11

A ball is thrown vertically upward.After t seconds its height(in feet)is given by the function h(t)=84t=16t^2.What is the maximu

m height that the ball will reach

1 answer:

Novay_Z [31]2 years ago

3 0

21 seconds!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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What is the slope of a line that is perpendicular to a line whose equation is 3y=−4x+2 ?

vova2212 [387]

we know that

if two lines are perpendicular, then the product of their slopes is equal to minus one

so

$m1*m2=-1$

Step 1

<u>Find the slope of the given line</u>

we have

$3y=-4x+2$

Solve for y

Divide by $3$ both sides

$3y/3=(-4x+2)/3$

$y=-\frac{4}{3}x+ \frac{2}{3}$

the slope of the given line is $m1=-\frac{4}{3}$

Step 2

<u>Find the slope of a line that is perpendicular to the given line</u>

we have

$m1=-\frac{4}{3}$

$m1*m2=-1$

$m2=-1/m1$

substitute the value of m1

$m2=-1/(-4/3)=\frac{3}{4}$

therefore

<u>the answer is</u>

the slope is $\frac{3}{4}$

4 0

3 years ago

Find two numbers, if their sum is 49 and their difference is 1/2 .

amm1812

Answer:

$x=24\frac{3}{4}\\ y=24\frac{1}{4}$

Step-by-step explanation:

Let the two numbers be x and y

So we have:

$x +y = 49\\x-y=\frac{1}{2}$

using the elimination method, add the two equations together:

$2x=49\frac{1}{2} \\2x=\frac{99}{2}$

solve for x:

$x=\frac{99}{4}\\x=24\frac{3}{4}$

substitute our value for x back into the first equation we made:

$x+y=49\\(\frac{99}{4}) + y=49\\y=49-\frac{99}{4}\\y=\frac{97}{4} \\ y=24\frac{1}{4}$

therefore,

$x=24\frac{3}{4}\\ y=24\frac{1}{4}$

6 0

3 years ago

830000 in scientific notation

DedPeter [7]

Answer:

8.3 * 10 ^5

Step-by-step explanation:

830000

To change this to scientific notation, we move the decimal 5 places to the left. The exponent will be positive 5 because we moved it to the left

8.3 * 10^ +5

8.3 * 10 ^5

4 0

3 years ago

Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co

ycow [4]

Answer:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

$y= x^2 -6x +14$

We can complete the square like this:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

4 0

3 years ago

Can you graph a line if its slope is undefined? Explain.

JulijaS [17]

You can but it would be going straight up and down

6 0

3 years ago