Answer:
21 ft by 28 ft
Step-by-step explanation:
To maximize the area, see the attached.
Perimeter will be 4l+3w which is equal to the fencing perimeter, given as 168
4l+3w=168
Making l the subject then
4l=168-3w
l=42-¾w
Area of individual land will be lw and substituting l with l=42-¾w
Then
A=lw=(42-¾w)w=42w-¾w²
A=42w-¾w²
Getting the first derivative of the above with respect to w rhen
42-w6/4=0
w6/4=42
w=42*4/6=28
Since
l=42-¾w=42-¾(28)=21
Therefore, maximum dimensions are 21 for l and 28 for w
Answer:
Step-by-step explanation:
We want to find sin(θ) and cos(θ) given that tan(θ) = 1/4 and sin(θ) > 0.
First, since tan(θ) and sin(θ) are both positive, cos(θ) must be positive as well.
Recall that tangent is the ratio of the opposite side to the adjacent side.
Therefore, the hypotenuse is:
So, with respect to θ, the opposite side is 1, the adjacent is 4, and the hypotenuse is √17.
Then it follows that:
And that:
Answer: N0. There are not enough teacher signatures.
<u>Step-by-step explanation:</u>
Total signatures needed: x 1200 = 150
Total signatures received: 150
********************************************************************
Teacher signatures needed: x 150 = 6
Teacher signatures received: x 150 = 4
<em>Side note: If there are student signatures then there are
teacher signatures, because the student plus teacher signatures must equal 100%</em>