Answer:
21 ft by 28 ft
Step-by-step explanation:
To maximize the area, see the attached.
Perimeter will be 4l+3w which is equal to the fencing perimeter, given as 168
4l+3w=168
Making l the subject then
4l=168-3w
l=42-¾w
Area of individual land will be lw and substituting l with l=42-¾w
Then
A=lw=(42-¾w)w=42w-¾w²
A=42w-¾w²
Getting the first derivative of the above with respect to w rhen
42-w6/4=0
w6/4=42
w=42*4/6=28
Since
l=42-¾w=42-¾(28)=21
Therefore, maximum dimensions are 21 for l and 28 for w
Explanation:
This question's it's about the order of operations. P-parenthesis, E-exponents, M-multiply, D-divide, A-add, and S-subtract. It can also go left to right.
Do exponents first.
Then, multiply left to right.
And add/subtract left to right.
Hope this helps!
Thanks!
Have a great day!
Answer:
see explanation
Step-by-step explanation:
The perimeter is the length of all the sides in the figure.
The arc of the semi- circle is included in this.
length of arc = πd ← d is the diameter
here d = 8, hence
arc = π × 8 = 4π ← exact length
Perimeter = 10 + 8 + 10 + 4π ≈ 40.57 in ( nearest hundredth )