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andrezito [222]
3 years ago
11

a fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closest to

the volume of water in the fishbowl in cubic inches?
Mathematics
2 answers:
NISA [10]3 years ago
7 0

Answer:

2,144.66 in³

Step-by-step explanation:

∵ The volume of a sphere,

V=\frac{4}{3}\pi (r)^3

Where,

r = radius of the sphere,

If Diameter of a sphere = 16 inches,

Then the radius of the sphere, r = \frac{16}{2} = 8 inches

So, the volume of the sphere,

V=\frac{4}{3}\pi (8)^3

=\frac{4}{3}\times 512

=2144.66058485

\approx 2144.66\text{ square inches }

∵ the  fishbowl shaped like a sphere having diameter 16 in is filled with water.

Thus, the volume of the water in the fish bowl = volume of sphere having diameter 16 inches

=  2,144.66 in³

gregori [183]3 years ago
6 0

Answer:

The volume of the water in the fishbowl is equal to

(682\frac{2}{3})\pi\ in^{3}  or  2,144.6\ in^{3}

Step-by-step explanation:

we know that

The volume of the sphere (a fishbowl) is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

r=16/2=8\ in ----> the radius is half the diameter

substitute

V=\frac{4}{3}\pi (8^{3})=\frac{2,048}{3}\pi\ in^{3}

convert to mixed number

\frac{2,048}{3}\pi\ in^{3}=\pi (\frac{2,046}{3}+\frac{2}{3})=(682\frac{2}{3})\pi\ in^{3}

(3.14156)*(682\frac{2}{3})=2,144.6\ in^{3}

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