Subtract 2.1 from both sides:

Add 1.4y to both sides:

Of course, we can rewrite this as

Divide both sides by 1.4

(r + 2) ÷ 1/2
Hope this helps you
Brainliest would be appreciated!
-AaronWiseIsBae
Let L be the low copper alloy and H be the high copper alloy.
We need 0.15L + 0.60H = 0.42 and L + H = 100
L=100 - H
Substituting this into the second equation for L, we get:
0.15(100-H) + 0.60H = 0.42(H+L)
15 - 0.15H + 0.60H = 0.42(H+100-H)
15 + 0.45H = 0.42(100)
0.45H = 42 - 15 = 27
H = 27/.45 = 60 lbs
Back substitution, L = 40 lbs.
The defensive area is 510 square yards
Step-by-step explanation:
Let L be the length of the rectangle
and
W be the width
According to given statement
L = 2W-15
Perimeter = 270

Dividing both sides by 6

We have to find the area first to find the defensive area
So,

Defensive area = 3/25 of total area
So,

Hence,
The defensive area is 510 square yards
Keywords: Area, Rectangle
Learn more about area at:
#LearnwithBrainly
25/100 is divisible by 25, so the simplest form is 1/4