Answer:
General Solution is 
and the particular solution is 
Step-by-step explanation:
This is a linear diffrential equation of type
..................(i)
here 
The solution of equation i is given by
we have ![e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}](https://tex.z-dn.net/?f=e%5E%7B%5Cint%20p%28x%29dx%7D%3De%5E%7B%5Cint%20%5Cfrac%7B-2%7D%7Bx%7Ddx%7D%5C%5C%5C%5Ce%5E%7B%5Cint%20%5Cfrac%7B-2%7D%7Bx%7Ddx%7D%3De%5E%7B-2ln%28x%29%7D%5C%5C%5C%5C%3De%5E%7Bln%28x%5E%7B-2%7D%29%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%5C%5C%5C%5C%5Cbecause%20e%5E%7Bln%28f%28x%29%29%7D%3Df%28x%29%5D%5C%5C%5C%5CThus%5C%5C%5C%5Ce%5E%7B%5Cint%20p%28x%29dx%7D%3D%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%7D)
Thus the solution becomes
This is the general solution now to find the particular solution we put value of x=2 for which y=6
we have 
Thus solving for c we get c = -1/2
Thus particular solution becomes
Answer:
6m+24
Step-by-step explanation:
basically you multiply m and 4 by six soooo
6 times m is 6x
6 times 4 is 24
soo
6m+24 is correct
can i have rainliest pleaseee:)b
16/3 1/2= 7/32. so you would measure 7/32 on the 16 cup scoop
Answer:
second option
Step-by-step explanation:
Given
x² - 6x - 33 = 0 ( add 33 to both sides )
x² - 6x = 33
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 3)x + 9 = 33 + 9
(x - 3)² = 42 → second option
Salutations!
To round to the nearest tenth, you need know whether the number next to tenth place is greater than 5 or lesser than 5. If its greater than 5, you need to round up. If its lesser than 5, you need to round down. Now, in the number 26.99 9 is in the tenth place. The number next to 9 is greater than 5, so just add on to the ones place, making the tenth and hundredth place 0. Zero has no value so whether you add the zero or not, it does not matter.
<span>26.99 round to the nearest tenth </span>≈ 27
Hope I helped (:
Have a great day!
