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3 years ago

What is the value of the number one in 61

Mathematics

2 answers:

ikadub [295]3 years ago

5 0

<span>the value of the number one in 61 is 1
hope it helps</span>

strojnjashka [21]3 years ago

5 0

The value of the number one in 61 is one

hope this helps

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NEED HELP!!!

AnnyKZ [126]

Answer:

see explanation

Step-by-step explanation:

(1)

$\frac{6}{2}$ = $\frac{4}{p}$ ( cross- multiply )

6p = 8 ( divide both sides by 6 )

p = $\frac{8}{6}$ = $\frac{4}{3}$

(2)

$\frac{n}{4}$ = $\frac{8}{7}$ ( cross- multiply )

7n = 32 ( divide both sides by 7 )

n = $\frac{32}{7}$

(3)

$\frac{5}{3}$ = $\frac{x}{4}$ ( cross- multiply )

3x = 20 ( divide both sides by 3 )

x = $\frac{20}{3}$

6 0

3 years ago

PLEASE HELP<br> I have no idea how to do this

tresset_1 [31]

Answer:

1st 2nd or both's answer you want

7 0

3 years ago

Which of the following is a line in the drawing?

Luba_88 [7]

Answer:

Step-by-step explanation:

It is the only segment that does not have a bend.

8 0

3 years ago

F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)

Butoxors [25]

Answer:

The function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

Explanation:

Given the functions;

$\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}$

Solving for the function;

$(g\circ f)(x)=g(f(x))$

so, we have;

$\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}$

Therefore, the function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

5 0

1 year ago

Which of these rational numbers is also an integer? 2/4, 4/2, 0.24, 2.4

Luda [366]

4/2 because 4/2=2 that is an integer

7 0

3 years ago

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