Answer:
The midpoint is (5/2, -15/2)
Step-by-step explanation:
The x coordinate of the midpoint is the average of the x coordinates
(1+4)/2 = 5/2
The y coordinate of the midpoint is the average of the x coordinates
(1+-16)/2 = -15/2
The midpoint is (5/2, -15/2)
V(t)=t^2+2t+1 integrating we get d(t)
d(t)=t^3/3+t^2+t or more neatly
d(t)=(t^3+3t^2+3t)/3 so
d(2)=(8+12+6)/3
d(2)=26/3
So the particle moves 9 feet (to the nearest foot) in the first two minutes.
STOP MAKING ME TYPE 20 CHARACTERS OMGG
the correct answer is 7cm