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murzikaleks [220]
2 years ago
9

Is anyone able to answer this for me? GIVING BRAINLIEST! hurry!

Mathematics
1 answer:
svetoff [14.1K]2 years ago
5 0
Nicoles pattern:

1
5
17
53
161

Ian’s pattern:

0
1
3
7
15

Ordered pair:

(1, 0)
(5, 1)
(17, 3)
(53, 7)
(161, 15)



Table 1 -

Sequence 1:

9
11
13
15
17

Sequence 2:

5
8
11
14
17

Ordered pair:

(9, 5)
(11, 8)
(13, 11)
(15, 14)
(17, 17)

Table 2 -

Sequence 1:

20
16
12
8
4

Sequence 2:

20
17
14
11
8

Ordered pair:

(20, 20)
(16, 17)
(12, 14)
(8, 11)
(4, 8)

Table 3 -

Sequence 1:

1
3
7
15
31

Sequence 2:

40
24
16
12
10

Ordered pair:

(1, 40)
(3, 24)
(7, 16)
(15, 12)
(31, 10)
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On the basis of data collected during an experiment, a biologist found that the growth of a fruit fly population (Drosophila) wi
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Answer:

(a). 15

(b). 78

Step-by-step explanation:

Growth of the population of a fruit fly is modeled by

N(t) = \frac{600}{1+39e^{-0.16t} }

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(a). For t = 0 [Initial population]

N(0) = \frac{600}{1+39e^{-0.16\times 0} }

       = \frac{600}{1+39}

       = \frac{600}{40}

       = 15

Initial population of the fruit flies were 15.

(b).Population of the fruit fly colony on 11th day.

N(11) = \frac{600}{1+39e^{-0.16\times 11} }

       = \frac{600}{1+39e^{-1.76} }

       = \frac{600}{1+39\times 0.172 }

       = \frac{600}{1+6.71}

       = \frac{600}{7.71}

       = 77.82

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On 11th day number of fruit flies colony were 78.

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