Make an algebraic expression for each plan.
For an instance, x represents the number of movies, and y represents the number of months
⇒ The expression for the digital movie plan is 3x
⇒ The expression for the DVD plan is 10y + 0.5x
A person rents movies in a month (that means the value of y equals 1), the expression of the DVD plan would be 10(1) + 0.5x = 10 + 0.5x
Find the value of x when the cost of both plan are the same
The two options will cost the same when the expression for digital movie is equal to the expression for DVD
the digital movie plan = the DVD plan
3x = 10 + 0.5x
Solve for x
3x - 0.5x = 10
2.5x = 10
x = 10/2.5
x = 4
The two options will cost the same, if the person rents 4 movies
4x^2 - 2xy^2
5xy^2 +
3x^2y
_____________
12x^5y^4-2xy^2
This is so because 4+5+3 is 12, then using laws of indices to add your x and y you get x^5 and y^4
To simplify your answer to the lowest you have it in the form of
3x^2y^2(4x^2y - 2xy^2)
If you multiply this as well you get the same answer I got with the addition
You forgot to put the picture
-24/150
-12/75
-4/25
-4/25 is the answer
