Answer:
b. + 1.01 V
Explanation:
Sn(s) ⇒ Sn2+ + 2e⁻ Eox = 0.14 V
Ag₊ + e⁻⇒ Ered = 0.80 V
_______________________________
Sn(s) + Ag⁺(aq) ⇒ Sn2⁺(aq) + Ag(s) Eºcell = 0.14 V + 0.80 V = 0.94 V
This problem is solved by using the Nernst equation:
Ecell = Eºcell - (0.0592 / n) log Q
since we are not at standard condition given that the concentrations are not at 1 M. So we will calculate Q first
Q = ( Sn²⁺ ) / ( Ag⁺) = 0.022/2.7 = 0.0081
Ecell = 0.94 V -(0.0592/2) x log (0.0081) = 1.00 V
Answer:
Sodium Bicarbonate on decomposition produces Carbon dioxide gas and Water vapors.
<span> 2 NaHCO</span>₂<span> </span> →<span> Na</span>₂<span>CO</span>₃<span> (s) </span>+ <span> CO</span>₂<span> (g) + H</span>₂<span>O (g)
</span>
Explanation:
Let suppose you burn 168 g ( 2 moles ) of NaHCO₃, a gas will produced and product is left behind. On measuring the product formed it will be almost equal to 105 g. This shows that the product is Na₂CO₃ and 1 mole of it is being produced after decomposition of sodium bicarbonate.
Answer: 3.306 mmol
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
![Molarity=\frac{n\times 1000}{V_s}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7Bn%5Ctimes%201000%7D%7BV_s%7D)
where,
Molarity
n= moles of solute
= volume of solution in ml
![C_2O_4H_2.2H_2O\rightarrow C_2O_4^{2-}+2H^++2H_2O](https://tex.z-dn.net/?f=C_2O_4H_2.2H_2O%5Crightarrow%20C_2O_4%5E%7B2-%7D%2B2H%5E%2B%2B2H_2O)
According to stoichiometry:
1 mole of
gives 2 moles of ![H^+](https://tex.z-dn.net/?f=H%5E%2B)
1.653 mmol of
gives =
of ![H^+](https://tex.z-dn.net/?f=H%5E%2B)
Thus number of millimoles of
are 3.306
Chemistry affects all aspects of life and most natural events because all living and nonliving things are made of matter.