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EastWind [94]
3 years ago
11

Which reaction does not occur?

Chemistry
1 answer:
balu736 [363]3 years ago
7 0

Answer: 2HF(aq)+Cl_2(g)\rightarrow F_2(g)+2HCl(aq) will not occur.

Explanation:

A single replacement reaction is one in which a more reactive element displaces a less reactive element from its salt solution. Thus one element should be different from another element.

A general single displacement reaction can be represented as :

X+YZ\rightarrow XZ+Y

a) 2HF(aq)+Cl_2(g)\rightarrow F_2(g)+2HCl(aq)

Flourine is more reactive than chlorine and hence this reaction cannot occur.

b) 2Na(s)+ZnF_2(aq)\rightarrow 2NaF(aq)+Zn(s)

Sodium is more reactive than zinc and hence the reaction will occur.

c) Fe(s)+CuCl_2(aq)\rightarrow FeCl_2(aq)+Cu(s)

Iron is more reactive than copper and hence the reaction will occur.

d) 2HCl(aq)+Mg(s)\rightarrow MgCl_2(aq)+H_2(g)

Magnesium is more reactive than hydrogen and hence the reaction will occur.

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What do you mean by environment conservation?​
BARSIC [14]

Explanation:

Environment conservation is an umbrella term that defines anything we do to protect our planet and conserve its natural resources so that every living thing can have an improved quality of life. bolivianouft and 7 more users found this answer helpful.

3 0
3 years ago
Sonja and Jeremy performed several experiments to show how changes in temperature affected the volume of an inflated balloon. Th
ycow [4]

Answer:

They also showed the effects of pressure on volume if temperature stayed the same

Explanation:

They also showed the effects of pressure on volume if temperature stayed the same is the experiment that will provide an evidence for Boyle's law.

Boyle's law states that "the volume of a fixed mass of a gas varies inversely as the pressure changes, if the temperature is constant".

  • The law is an affirmation of what happens when there is a dynamics between pressure and volume if temperature is made constant.
  • So the experiment designed to investigate this proves and shows Boyle's law.
8 0
3 years ago
Read 2 more answers
What factors affect the dynamic state of equilibrium in a chemical reaction and how?
yanalaym [24]

Answer:

Only changes in temperature will influence the equilibrium constant K_c. The system will shift in response to certain external shocks. At the new equilibrium Q will still be equal to K_c, but the final concentrations will be different.

The question is asking for sources of the shocks that will influence the value of Q. For most reversible reactions:

  • External changes in the relative concentration of the products and reactants.

For some reversible reactions that involve gases:

  • Changes in pressure due to volume changes.

Catalysts do not influence the value of Q. See explanation.

Explanation:

\displaystyle K_c = {e}^{\Delta G/(R\cdot T)}.

Similar to the rate constant, the equilibrium constant K_c depends only on:

  • \Delta G the standard Gibbs energy change of the reaction, and
  • T the absolute temperature (in degrees Kelvins.)

The reversible reaction is in a dynamic equilibrium when the rate of the forward reaction is equal to the rate of the backward reaction. Reactants are constantly converted to products; products are constantly converted back to reactants. However, at equilibrium Q = K_c the two processes balance each other. The concentration of each species will stay the same.

Factors that alter the rate of one reaction more than the other will disrupt the equilibrium. These factors shall change the rate of successful collisions and hence the reaction rate.

  • Changes in concentration influence the number of particles per unit space.
  • Changes in temperature influence both the rate of collision and the percentage of particles with sufficient energy of reaction.

For reactions that involve gases,

  • Changing the volume of the container will change the concentration of gases and change the reaction rate.

However, there are cases where the number of gases particles on the reactant side and the product side are equal. Rates of the forward and backward reaction will change by the same extent. In such cases, there will not be a change in the final concentrations. Similarly, catalysts change the two rates by the same extent and will not change the final concentrations. Adding noble gases will also change the pressure. However, concentrations stay the same and the equilibrium position will not change.

8 0
3 years ago
#2: A gas at unknown pressure and a volume of 66 cm has its pressure changed to 150 kPa. The new volume
Murljashka [212]

Answer:

<h2>377 kPa</h2>

Explanation:

The original pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the original pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

150 kPa = 150,000 Pa

We have

P_1 =  \frac{150000 \times 166}{66}  =  \frac{24900000}{66}  \\  = 377272.72...

We have the final answer as

<h3>377 kPa</h3>

Hope this helps you

7 0
3 years ago
What is the structure of an artery ?
wariber [46]
Well this is a bio question but it goes the tunica interna the tunica media then the tunica externa.
8 0
3 years ago
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