Answer:
No
Explanation
I say no because that could possibly put many species of animals i danger of nuclear reaction. Not only would it put many animals in danger it would put humans plant and most likely make that area a toxic waste for years
Answer:
29.0 g
Explanation:
We know that we will need a chemical equation with masses and molar masses, so let’s start by gathering all the information in one place.
: 63.55 46.01
Cu + 4HNO₃ ⟶ Cu(NO₃)₂ + 2NO₂ + 2H₂O
Mass/g: 20.0
1. Use the molar mass of Cu to calculate the moles of Cu.
![\text{Moles of Cu} = \text{20.0 g Cu}\times \frac{\text{1 mol Cu} }{\text{63.55 g Cu}}= \text{0.3147 mol Cu}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20Cu%7D%20%3D%20%5Ctext%7B20.0%20g%20Cu%7D%5Ctimes%20%5Cfrac%7B%5Ctext%7B1%20mol%20Cu%7D%20%7D%7B%5Ctext%7B63.55%20g%20Cu%7D%7D%3D%20%5Ctext%7B0.3147%20mol%20Cu%7D)
2. Use the molar ratio of NO₂:Cu to calculate the moles of NO₂.
![\text{Moles of NO}_{2} = \text{0.3147 mol Cu} \times \frac{\text{2 mol NO$_{2}$}}{\text{1 mol Cu}} = \text{0.6294 mol NO}_{2}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20NO%7D_%7B2%7D%20%3D%20%5Ctext%7B0.3147%20mol%20Cu%7D%20%5Ctimes%20%5Cfrac%7B%5Ctext%7B2%20mol%20NO%24_%7B2%7D%24%7D%7D%7B%5Ctext%7B1%20mol%20Cu%7D%7D%20%3D%20%5Ctext%7B0.6294%20mol%20NO%7D_%7B2%7D)
3. Use the molar mass of NO₂ to calculate the mass of NO2.
![\text{Mass of NO}_{2} = \text{0.6294 mol NO$_{2}$}\times \frac{\text{46.01 g NO$_{2}$} }{\text{1 mol NO$_{2}$}}= \text{29.0 g NO}_{2}](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20NO%7D_%7B2%7D%20%3D%20%5Ctext%7B0.6294%20mol%20NO%24_%7B2%7D%24%7D%5Ctimes%20%5Cfrac%7B%5Ctext%7B46.01%20g%20NO%24_%7B2%7D%24%7D%20%7D%7B%5Ctext%7B1%20mol%20NO%24_%7B2%7D%24%7D%7D%3D%20%5Ctext%7B29.0%20g%20NO%7D_%7B2%7D)
Answer:
The thermal energy of an object is the total energy of the particles in a material. A 5-kg chunk of aluminum and a 5-kg block of silver that are at the same temperature have the same thermal energy. Heat flows from a higher temperature to a lower temperature.
Answer: 3.26x10^5L
Explanation:
P1 = 101kPa
P2 = 95kPa
T1 = 27°C = 27 +273 =300k
T2 = —10°C = —10 +273 = 263k
V1 = 3.5 x 10^5 L
V2 =?
P1V1 / T1 = P2V2 /T2
(101 x 3.5 x 10^5)/300 = (95xV2)/263
300x95xV2 = 101x 3.5x10^5x263
V2 = (101x 3.5x10^5x263) /(300x95)
V2 = 3.26x10^5L