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andrey2020 [161]
3 years ago
8

Graph the exponential function. y = 4(3) x

Mathematics
2 answers:
rusak2 [61]3 years ago
7 0
Y=12x so basically on ur graph you would start at 0 since you have no y intercept and go up 12 spaces and over one to the right and keep doing that
gtnhenbr [62]3 years ago
7 0

Answer:

The answer is the attached graph.

Step-by-step explanation:

We have to know about exponential function.

The general Exponential Function is:

f(x)=a^x

Where:

a is any value greater than 0

Properties depend on value of "a"

  1. When a=1, the graph is a horizontal line at y=1
  2. It is always greater than 0, and never crosses the x-axis
  3. It always intersects the y-axis at y=1, that it means, it passes through (0,1)
  4. Its Domain is the Real Numbers: R
  5. Its Range is the Positive Real Numbers: (0, +∞)

I have attached an image that shows the graph of y=4*3^x

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Line a passes through the points (-1,0) and (3,-8)<br> what’s the slope?
konstantin123 [22]

Answer: 2

Step-by-step explanation:

(x1,y1) = (-1,0)

(x2,y2) = (3,8)

m = (8–0)/(3-(-1))

m = 8/(3+1)

m = 8/4

m = 2

8 0
2 years ago
A rectangle is placed around a semicircle as shown below. The length of the rectangle is 14mm. Find the area of the shaded regio
Damm [24]

Image is missing, so i have attached it

Answer:

21.07 mm²

Step-by-step explanation:

We will use the Formulas:

Area of semicircle = πr²/2

Area_rectangle = Length x width = Lw

We are given:

Length of rectangle = 14 mm

From the attached image, the diameter of the semicircle is equal to the length of the rectangle.

Thus;

diameter of semicircle = length of rectangle

Therefore,

diameter of semicircle = 14 mm

Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.

Thus;

diameter of semicircle/2 = radius of semicircle

Hence;

radius of semicircle = 14/2 = 7mm = width of rectangle

Thus;

Area of rectangle = L*w = 14 × 7 = 98 mm²

Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²

To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.

Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²

7 0
3 years ago
Rachel has a toy shaped like a triangular pyramid in which the base and the lateral faces are congruent equilateral triangles. T
astra-53 [7]
The lateral area that Rachel needs to cover is 21 inches.
7 0
3 years ago
What’s the value of x?
GaryK [48]

12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc

7 0
3 years ago
Given P(-7,3,-7) and Q(-4,-3,-9), find the midpoint of the segment PQ
Alona [7]

Answer:

The coordinates of the midpoint of the segment are (-5.5,0,-8)

Step-by-step explanation:

In this question, we are tasked with calculating the midpoint of the segment PQ.

To calculate this, we employ the use of a mathematical formula as follows;

The coordinate of the midpoint are = {(x1+x2)/2, (y1+y2)/2 , (z1+ z2)/2}

Thus we have;

{(-7-4)/2, (3-3)/2 , (-7-9)/2} = (-11/2, 0/2, -16/2)

= (-5.5,0,-8)

4 0
3 years ago
Read 2 more answers
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