By either long or synthetic division, it's easy to show that
The quartic will be exactly divisible by
when the numerator of the remainder term vanishes, or for those values of
such that
I'm not sure how to count the number of solutions (software tells me it should be 80), but hopefully this is a helpful push in the right direction.
<u><em>Answer:</em></u>
<u><em /></u>
<u><em>Explanation:</em></u>
<u>Before we begin, remember the following rules:</u>
<u>1- Distribution property:</u>
<u />
<u>2- Simplification of fractions:</u>
<u />
<u>3- Signs in multiplication:</u>
+ve * +ve = +ve
-ve * -ve = +ve
+ve * -ve = -ve
<u>Now, for the given problem, we have:</u>
<u></u>
<u>Starting with the distributive property:</u>
<u />
..................>This corresponds to option 1
<u>Now, we simplify the output from the above step:</u>
<u />
................> This corresponds to option 5
Hope this helps :)
24,000,300
Step-by-step explanation:
you mean twenty-four million and three hundred right? or Twenty million and three hundred thousand?
because that's not possible.
Answer:
Step-by-step explanation:
The diagram is drawn and attached below.
From the diagram
