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KIM [24]
3 years ago
5

Dx/dy - snn(x + y) = 0 Ecuación separable

Mathematics
1 answer:
borishaifa [10]3 years ago
4 0

Answer:

Step-by-step explanation:

\frac{dx}{dy} -sin (x+y)=0\\put~x+y=t\\diff .~w.r.t. ~y\\\frac{dx}{dy} +1=\frac{dt}{dy} \\\frac{dx}{dy} =\frac{dt}{dy} -1\\\frac{dt}{dy}-1-sin ~t=0\\\frac{dt}{dy} =1+sin~t\\separate~the ~variables~and~integrating\\\ \int\ {\frac{1}{1-sin~t} } \, dt =\int\ {1} \, dy   \\\int\  {\frac{1+ sin~t}{1-sin^2 ~t} } \, dt=y+c\\\int\ {(sec^2t-sec~t~tan~t)} \, dt=y+c\\ tan t-sec t=y+c\\tan(x+y)-sec(x+y)=y+c

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