She could switch them around by grouping them into groups of 4s, 3s, 2s, or 5s.
Answer: they’re both 53
Step-by-step explanation:
i just took the test and it is correct
Answer: 
<u>Step-by-step explanation:</u>
y = A cos (Bx - C) + D
- A (amplitude) = max - D
- B = Period/2π ---> Period is the distance from max to next max
- C = B · Phase Shift ---> Phase shift is distance from y-axis to max
- D (vertical shift) = (max + min)/2
D = (max + min)/2 = (3 - 11)/3 = -4
A = max - D = 3 - (-4) = 7
Period = 9π/4 - π/4 = 8π/4 = 2π
B = Period/2π = 2π/2π = 1
Phase Shift = π/4 - 0 = π/4
C = B · Phase Shift = 1 · π/4 = π/4
Equation:
y = 7 cos (1·x - π/4) + (-4)
<span>Simplifying
3x + 10 = 5x + 22
Reorder the terms:
10 + 3x = 5x + 22
Reorder the terms:
10 + 3x = 22 + 5x
Solving
10 + 3x = 22 + 5x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-5x' to each side of the equation.
10 + 3x + -5x = 22 + 5x + -5x
Combine like terms: 3x + -5x = -2x
10 + -2x = 22 + 5x + -5x
Combine like terms: 5x + -5x = 0
10 + -2x = 22 + 0
10 + -2x = 22
Add '-10' to each side of the equation.
10 + -10 + -2x = 22 + -10
Combine like terms: 10 + -10 = 0
0 + -2x = 22 + -10
-2x = 22 + -10
Combine like terms: 22 + -10 = 12
-2x = 12
Divide each side by '-2'.
x = -6
Simplifying
x = -6</span>
Answer:
A =28 pi cm^2
Step-by-step explanation:
First find the area of the larger circle
A = pi r^2
A = pi (8)^2
A = 64 pi
Find the area of the smaller circle
A = pi r^2
A = pi 6^2
A = 36 pi
The shaded area is the larger circle minus the smaller circle
A shaded = 64 pi - 36 pi
A =28 pi cm^2
