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san4es73 [151]
2 years ago
11

Which postulate proves that these two triangles are congruent?

Mathematics
1 answer:
crimeas [40]2 years ago
7 0
Answer
SAS

cause
EF = HJ
<F = <J
FD = GJ
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Can someone help me with this.?
prohojiy [21]

Answer:

Below.

Step-by-step explanation:

To find the answer, you have to compare the two equations:

y=\frac{1}{10}x+60 and y=\frac{1}{5}

So first, the graph looks different because the two slopes are different. The first one will be more vertical than the second one.

The second difference is the y - intercepts. The first equation starts at (0, 60) and the second starts at the origin.

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3 years ago
WORTH 60 POINTS! PLZ HELP! BRAINLIEST OPPORTUNITY!
makkiz [27]

Answer:

x = 10

Step-by-step explanation:

2) -3x + 17 = -x - 3

4) 20 = 2x

1) -3x + 12 + 5 = -x -3

5) 10 = x

3) 17 = 2x - 3

<u>-3(x - 4) + 5 = -x - 3</u>

<u>-3x + 12 + 5 = -x - 3</u>

<u>-3x + 17 = -x -3</u>

<em>+3x          +3x</em>

<u>17 = 2x - 3</u>

<em>+3        + 3</em>

<u>20 = 2x</u>

<u>10 = x</u>

<u />

I hope that this helps! :)

5 0
3 years ago
At carl's combine diner, there are three size of coffee drinks regular (300ml), large (500ml) and extra large (800mL), and they
MariettaO [177]

Answer:

The number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

Step-by-step explanation:

Given that the cost for regular coffee drinks (300 ml)=$2.25

The cost for large coffee drinks (500 ml)=$3.25

The cost for extra large coffee drinks (800 ml)=$5.75

Let p,q, and r be the number of regular, large, and extra-large coffee sold.

As the diner sold a total of 37 coffees, so

p+q+r=37

r=37-p-q...(i)

The volume of p regular coffee = 300p ml

The volume of q  large coffee = 500q ml

The volume of r extra-large coffee = 800r ml

As the total volume of coffee sold was 19,100mi, so

300p+500q+800r=19100

By using equation (i)

300p+500q+800(37-p-q)=19100

300p+500q+800 x 37 - 800p - 800q=19100

-500p-300q=19100-29600

500p+300q=10500

500p=10500-300q

p=21-0.6q...(ii)

Now, the cost of p regular coffee=$2.25p

The cost of q large coffee=$3.25q

The cost of r extra-large coffee=$5.75r

As the amount of money made in coffee sales was $133.25, so

2.25p+3.25q+5.75r=133.25

By using equations (1)  we have

2.25p+3.25q+5.75(37-p-q)=133.25

2.25p+3.25q+212.75-5.75p-5.75q=133.25

3.50p+2.50q=79.5

From equation (ii)

3.5(21-0.6q)+2.50q=79.5

73.5-2.1q+2.5q=79.5

0.4q=79.5-73.5=6

q=6/0.4

q=15

From equation (ii)

p=21-0.6(15)

p=12

From equation (i)

r= 37-12-15

r=10

Hence, the number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

5 0
3 years ago
Pls help I really need this help I’ll try to give extra points
kicyunya [14]

Answer:

c

Step-by-step explanation:

I GOT THE POWER OF GOD AND ANIME ON MY SIDE

3 0
2 years ago
Whats the answer??? Pleaseeee!!!!
kvasek [131]

To find the 20th term in this sequence, we can simply keep on adding the common difference all the way until we get up to the 20th term.

The common difference is the number that we are adding or subtracting to reach the next term in the sequence.

Notice that the difference between 15 and 12 is 3.

In other words, 12 + 3 = 15.

That 3 that we are adding is our common difference.

So we know that our first term is 12.

Now we can continue the sequence.

12 ⇒ <em>1st term</em>

15 ⇒ <em>2nd term</em>

18 ⇒ <em>3rd term</em>

21 ⇒ <em>4th term</em>

24 ⇒ <em>5th term</em>

27 ⇒ <em>6th term</em>

30 ⇒ <em>7th term</em>

33 ⇒ <em>8th term</em>

36 ⇒ <em>9th term</em>

39 ⇒ <em>10th term</em>

42 ⇒ <em>11th term</em>

45 ⇒ <em>12th term</em>

48 ⇒ <em>13th term</em>

51 ⇒ <em>14th term</em>

54 ⇒ <em>15th term</em>

57 ⇒ <em>16th term</em>

60 ⇒ <em>17th term</em>

63 ⇒ <em>18th term</em>

66 ⇒ <em>19th term</em>

<u>69 ⇒ </u><u><em>20th term</em></u>

<u><em></em></u>

This means that the 20th term of this arithemtic sequence is 69.

5 0
3 years ago
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