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Ierofanga [76]
4 years ago
5

5n+37 GFH 2+17EFG are a linear pair

Mathematics
1 answer:
Paha777 [63]4 years ago
5 0
NO. they are not. Nothing in this question or sentences make sense to a linear pair.
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The data set represents the total number of tickets each person purchased for a play.
Bezzdna [24]

Median: The middle number when all the numbers are listed in order.

First, we would put our numbers in order from least to greatest.

0 - 0 - 1 - 1 - 1 - 2 - 2 - 2 - 4 - 4

Next, we need to find the middle number. When we cross of one number from the left and one number from the right and keep doing this, we come across two numbers that are in the middle. The two numbers that are in the middle are 1 and 2. We find the median by adding 2 and 1 together to get a sum of 3 and then divide it by 2 to get an answer of 1.5

The median of this set of numbers is 1.5

4 0
3 years ago
(1.5 ? 10^2) X (2.0 ? 10^3) Express your answer in scientific notation and standard form.
ludmilkaskok [199]

Answer: 3*10^5 or 300,000 cant remember witch one it is

Step-by-step explanation:

1.5*10^2= 150

2*10^3=2,000

150*2000=300,000

3*10^5

4 0
3 years ago
Help pretty please .w.
sineoko [7]
I don’t know what that is it’s probably 9999999
4 0
3 years ago
Read 2 more answers
How many six-digit odd numbers are possible if the left digit cannot be zero?
melisa1 [442]
We are asked for the number of <span>six-digit odd numbers that can be formed. the left-most digit should not be zero because it make the number -five digit already. An odd number ends only in 1, 3, 5, 7 and 9. Using counting, the 6th digit can only have 5 numbers, the 5th, 4th, 3rd, and 2nd can have, 10 numbers. The first number can only have 9 numbers. Hence the total number is 450,000</span>
6 0
3 years ago
Find the solution set of the following quadratic equations using the quadratic formula.
oksian1 [2.3K]

Answer:

<h3>                1)  x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2</h3><h3>                2)   x_1=-\dfrac13\,,\quad x_2=-3    </h3>

Step-by-step explanation:

<h3>1)</h3>

x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2

<h3>2)</h3><h3>3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3</h3>
7 0
3 years ago
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