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3 years ago

5n+37 GFH 2+17EFG are a linear pair

Mathematics

1 answer:

Paha777 [63]3 years ago

5 0

NO. they are not. Nothing in this question or sentences make sense to a linear pair.

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Use the graphing tool to graph the function f(x)=10^x. Then identify the features of the graph.

mafiozo [28]

Answer:

Step-by-step explanation:

3 0

2 years ago

p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.

Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

$\frac{p}{q {r}^{2} } = k$

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

$\frac{200}{2(3) {}^{2} } = k$

$\frac{200}{18} = k$

$\frac{100}{9} = k$

Now, since we know our constant, let find p.

$\frac{p}{q {r}^{2} } = \frac{100}{9}$

Q is 5, and r is 2.

$\frac{p}{5( {2}^{2}) } = \frac{100}{9}$

$\frac{p}{20} = \frac{100}{9}$

$p = \frac{2000}{9}$

3 0

1 year ago

Two trains start from Fort Worth traveling at the same speed. The trip for Train W takes 20 hours, while the trip for Train Z ta

MrMuchimi

Answer:

The equation that best models this situation is :

b. $\frac{x}{20}=\frac{x+400}{25}$

Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = 2,000 miles

Step-by-step explanation:

Given:

Time taken for Train W to complete a trip = 20 hours

Time taken for Train Z to complete a trip = 25 hours

The city Train Z is traveling to is 400 miles farther away than the city Train W is traveling to.

both trains have same speeds and start from same location.

To find the distance in total each train travels.

Solution:

<em>Let length of the trip of Train W be </em>= $x$ miles

Speed of Train W can be given as :

⇒ $\frac{Distance}{Time}$

⇒ $\frac{x}{20}\ miles/h$

<em>So, the length of the trip of Train Z will be</em> = $(x+400)$ miles

Speed of Train Z can be given as :

⇒ $\frac{Distance}{Time}$

⇒ $\frac{x+400}{25}\ miles/h$

Since the speeds are same, so the equation to find $x$ can be given as:

⇒ $\frac{x}{20}=\frac{x+400}{25}$

Solving for $x$

Multiplying both sides by 100 to remove fractions.

⇒ $100\times \frac{x}{20}=100\times \frac{x+400}{25}$

⇒ $5x=4(x+400)$

Using distribution.

⇒ $5x=4x+1600$

Subtracting both sides by $4x$

⇒ $5x-4x=4x-4x+1600$

⇒ $x=1600$

Thus, Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = $1600+400$ = 2,000 miles

3 0

3 years ago

BRT,DBF,HIL,NPR,.....

Sergio039 [100]

OSOSPWBSWR F SDOSOEPW.,

4 0

2 years ago

Round 00.963.785 to the nearest. hundredth

vladimir1956 [14]

There are extra periods so I’m not exactly sure but I think it’s 00.96

6 0

1 year ago