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3 years ago

F(x) = |2x + 1| + 3

Mathematics

1 answer:

worty [1.4K]3 years ago

8 0

Answer:

(f + g)(x) = I2x + 1I + 1 ⇒ C

Step-by-step explanation:

Let us solve the question

∵ f(x) = I2x + 1I + 3

∵ g(x) = -2

→ We need to find (f + g)(x), which means add the two functions

∵ (f + g)(x) = f(x) + g(x)

→ Substitute the right side of each function on the right side

∴ (f + g)(x) = I2x + 1I + 3 + (-2)

→ Remember (+)(-) = (-)

∴ (f + g)(x) = I2x + 1I + 3 - 2

→ Add the like terms in the right side

∵ (f + g)(x) = I2x + 1I + (3 - 2)

∴ (f + g)(x) = I2x + 1I + 1

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SVETLANKA909090 [29]

Answer:

A. 2:3

Step-by-step explanation:

Both numbers are divisible by 6

12/6=2

18/6=3

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4 years ago

The city of Gary has a population of 75,282. Approximately 34.78% of Gary residents have a higher education degree. How many peo

NARA [144]

Answer:

26183

Step-by-step explanation:

Given that,

The population of the city of Gary is 75,282. 34.78% of Gary residents have a higher education degree.

We need to find the no of people in Gary have a higher education degree. It can be simply calcualted by taking 34.78% of 75,282 as follows :

$P=75282\times 34.78\%\\\\ =75282\times \dfrac{34.78}{100}\\\\=26183.07$

P = 26183

So, there are 26183 people in Gary have a higher education degree.

5 0

3 years ago

One institute mandates that for every 100 items scanned through the electronic checkout scanner at a retail store, no more than

ozzi

Answer:

There is a 20% probability that the store selected does not violate the institute scanner accuracy standard

Step-by-step explanation:

70 company stores were investigared.

56 violated the institute's scanner accuracy standard.

70-56 = 14 did not violate the institute scanner accuracy standard.

If 1 of the 70 company stores is randomly selected, what is the probability that that store does not violate the institute scanner accuracy standard?

This is 14 divided by 70, so:

$P = \frac{14}{70} = 0.2$

There is a 20% probability that the store selected does not violate the institute scanner accuracy standard

4 0

3 years ago

Plz help me with this...there might be errors in this but I'm not sure

Flura [38]

Step-by-step explanation:

1. cot(A − B)

From angle sum/difference equations, we know this equals:

cot(A − B) = (cot A cot B + 1) / (cot B − cot A)

But we also know it equals:

cot(A − B) = 1 / tan(A − B)

cot(A − B) = (1 + tan A tan B) / (tan A − tan B)

Setting the two equal to each other:

(cot A cot B + 1) / (cot B − cot A) = (1 + tan A tan B) / (tan A − tan B)

Writing tangent in terms of cotangent:

(cot A cot B + 1) / (cot B − cot A) = (1 + 1 / (cot A cot B)) / (tan A − tan B)

(cot A cot B + 1) / (cot B − cot A) = ((cot A cot B + 1) / (cot A cot B)) / (tan A − tan B)

(cot A cot B + 1) / (cot B − cot A) = (cot A cot B + 1) / ((cot A cot B) (tan A − tan B))

Divide both sides by the numerator:

1 / (cot B − cot A) = 1 / ((cot A cot B) (tan A − tan B))

Take inverse of both sides:

cot B − cot A = (cot A cot B) (tan A − tan B)

Solve for cot A cot B:

cot A cot B = (cot B − cot A) / (tan A − tan B)

cot A cot B = a / b

Now substitute into the first angle difference equation we wrote earlier:

cot(A − B) = (cot A cot B + 1) / (cot B − cot A)

cot(A − B) = (a / b + 1) / a

cot(A − B) = (a / b) / a + 1 / a

cot(A − B) = 1 / b + 1 / a

2. cos A / (1 ± sin A)

From angle sum/difference formulas, we know:

sin (90 ± A) = cos A

cos (90 ± A) = ∓ sin A

Substituting:

sin (90 ± A) / (1 − cos (90 ± A))

From half angle formula, this equals:

cot (45 ± A/2)

Using reflection:

-cot (-45 ∓ A/2)

And finally, phase shift:

tan (-45 ∓ A/2 + 90)

tan (45 ∓ A/2)

Check that you wrote the problem correctly. Looks like you switched ∓ with ±.

8 0

3 years ago

Who would be a member of the American Dental Association?

Kay [80]

I believe it would be a dental student.

6 0

3 years ago

Read 2 more answers